Concept explainers
(a)
Interpretation:
The skeletal structures for the given compounds has to be drawn including cis-trans isomers.
Concept introduction:
In skeletal structure or bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the heteroatoms are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Cis-trans terminology is used for two non-similar groups attached
If the two identical groups are attached on each side of double bond in same side, then it is cis alkenes.
If the two identical groups are attached on each side of double bond in opposite manner, then it is trans alkenes.
(b)
Interpretation:
The skeletal structures for the given compounds has to be drawn including cis-trans isomers.
Concept introduction:
In skeletal structure or bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the heteroatoms are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Cis-trans terminology is used for two non-similar groups attached alkenes.
If the two identical groups are attached on each side of double bond in same side, then it is cis alkenes.
If the two identical groups are attached on each side of double bond in opposite manner, then it is trans alkenes.
(c)
Interpretation:
The skeletal structures for the given compounds has to be drawn including cis-trans isomers.
Concept introduction:
In skeletal structure or bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the heteroatoms are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Cis-trans terminology is used for two non-similar groups attached alkenes.
If the two identical groups are attached on each side of double bond in same side, then it is cis alkenes.
If the two identical groups are attached on each side of double bond in opposite manner, then it is trans alkenes.
(d)
Interpretation:
The skeletal structures for the given compounds has to be drawn including cis-trans isomers.
Concept introduction:
In skeletal structure or bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the heteroatoms are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Cis-trans terminology is used for two non-similar groups attached alkenes.
If the two identical groups are attached on each side of double bond in same side, then it is cis alkenes.
If the two identical groups are attached on each side of double bond in opposite manner, then it is trans alkenes.
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
ORGANIC CHEMISTRY-W/S.G+SOLN.MANUAL
- Provide the following: 1. expanded structural formula 2. Molecular formula " CH3 CH2 | CH2 — CH2 — СH — CHF — CH2 — СНЗ CH2 CH3arrow_forwardPlease don't provide handwritten solution ...arrow_forward1. Although there is only one alkene with the formula C2H4 (ethene) and only one with the formula C3H6 (propene), there are several alkenes with the formula C4H8. Draw all of the possible bond line structures for alkenes with the formula C4H3 including all possible structural and stereoisomers.arrow_forward
- Done 5Ć 2.) On Table Q, take a look at the "Structural Formula" of all three classes of organic compounds you just named in the previous question. What are some similarities and differences between all three classes of these compounds? SIMILARITIES DIFFERENCES >> K Table Q Homologous Series General Formula Name ethane ethene CH₂-ethyne Name alkanes alkenes alkynes Note: sumber of carbon atoms Layout Backgrounds Photos Hydrocarbons Examples Structural Formula HH H-C C-H Ⓒ Stickers PIC COLLAGE Aa Textarrow_forwardA model of a cycloalkane appears in the window below. ball & stick + labels Which of the following represent structural isomers of the molecule shown in the model? Choose all that apply. n CH3-CHz-CH2-CH2-CH3 CH2. CCH-CH2-CH3 CH CH2. ссH—сHз CH CHз CH2 CH-CH3 сн CH2 CHз Cнз CH- CH2arrow_forwardWhich of the following options best describes the relationship between the structures shown below? O They are geometric isomers. They are the same molecule. They have different molecular formulas. They are constitutional isomers.arrow_forward
- Write the systematic name of each organic molecule: CH3 — structure CH2 || OH C-CH-CH3 HO–CH2–CH2–CH CH3 || C-CH2-OH || OH ད་རིས་ལས་མ་ CH3- CH-CH2OH CH3 name كarrow_forward3. Draw and name all of the constitutional isomers of C4H7Br3.arrow_forward(iii) In the presence of a suitable catalyst, 2-methylpropene forms a mixture of dimers. Two of these dimers react with hydrogen to form * 2,2,4-trimethylpentane. Draw the skeletal formula for 2,2,4-trimethylpentane. Use this to draw the skeletal structure of one of the dimers formed from 2-methylpropene. 2,2,4-trimethylpentane Dimerarrow_forward
- 5) Provide your own list of alkanes. They can not be the same structure but should all have the same number of carbons. (see the problem solving video for an example) Rank them in order of increasing melting point. You can not have the same example as someone else.arrow_forward'arrow_forwardIn the space below, redraw n-butane in this elongated conformation. All C atoms should be drawn in the plane of the paper in a zig-zag to represent the geometry displayed by your model kit. The hydrogen atoms should be attached to the carbon atoms via dashed and wedged bonds, as in question 4C above, to illustrate the three-dimensional geometry of the structure.arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co