Concept explainers
(a)
Find the unknown nuclei in the given reaction.
(a)
Answer to Problem 1Q
The unknown nuclei in the given reaction is
Explanation of Solution
The given reaction is,
In the given reaction the reactants have 56 protons and 138 nucleons which means 82 neutrons. Thus the product must have 56 proton and 138 nucleons. Therefore the unknown product must have 56 proton and 82 neutron. Then the unknown product is
Conclusion:
Therefore, the unknown nuclei in the given reaction is
(b)
Find the unknown nuclei in the given reaction.
(b)
Answer to Problem 1Q
The unknown nuclei in the given reaction is
Explanation of Solution
The given reaction is,
In the given reaction the reactants have 56 protons and 138 nucleons which means 82 neutrons. Thus the product must have 56 proton and 138 nucleons. Therefore the unknown product must have 1 proton and 0 neutron. Then the unknown product is
Conclusion:
Therefore, the unknown nuclei in the given reaction is
(c)
Find the unknown nuclei in the given reaction.
(c)
Answer to Problem 1Q
The unknown nuclei in the given reaction is
Explanation of Solution
The given reaction is,
In the given reaction the reactants have 2 protons and 4 nucleons which means 2 neutrons. Thus the product must have 2 proton and 4 nucleons. Therefore the unknown product must have 0 proton and 0 neutron. Then the unknown product is
Conclusion:
Therefore, the unknown nuclei in the given reaction is
(d)
Find the unknown nuclei in the given reaction.
(d)
Answer to Problem 1Q
The unknown nuclei in the given reaction is
Explanation of Solution
The given reaction is,
In the given reaction the reactants have 81 protons and 201 nucleons which means 120 neutrons. Thus the product must have 81 proton and 201 nucleons. Therefore the unknown product must have 80 proton and 119 neutron. Then the unknown product is
Conclusion:
Therefore, the unknown nuclei in the given reaction is
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Chapter 42 Solutions
Physics for Scientists and Engineers with Modern Physics
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- (a) Calculate the energy released in the neutron- Induced fission reaction n+235U92Kr+142Ba+2n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward(a) How many 239Pu nuclei must fission to produce a 20.0kT yield, assuming 200 MeV per fission? (b) What is the mass of this much 239Pu?arrow_forward(a) Neutron activation of sodium, which is 100% 23Na, produces 24Na, which is used in some heart scans, as seen in Table 32.1. The equation for the reaction is 23Na+n24Na+ . Find its energy output, given the mass of 24Na is 23.990962 u. (b) What mass at 24Na produces the needed 5.0mCi activity, given its halflife is 15.0 h?arrow_forward
- undergoes alpha decay, (a) Write the reaction equation, (b) Find the energy released in the decay.arrow_forward(a) Calculate the number of grams of deuterium in an 80.000L swimming pool, given deuterium is 0.0150% of natural hydrogen. (b) Find the energy released in joules if this deuterium is fused via the reaction 2H+2H3He+n. (c) Could the neutrons be used to create more energy? (d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.arrow_forward
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