The nature of marginal cost from the following options such that daily cost to imitation oil paintings is given by the function C ( x ) = 0.1 x 2 − 3.5 x + 500 dollars where x (the number of oil paintings) increases, options are given below: (A) increases (B) decreases (C) increases, then decreases (D) decreases, then increases
The nature of marginal cost from the following options such that daily cost to imitation oil paintings is given by the function C ( x ) = 0.1 x 2 − 3.5 x + 500 dollars where x (the number of oil paintings) increases, options are given below: (A) increases (B) decreases (C) increases, then decreases (D) decreases, then increases
Solution Summary: The author explains that the daily cost to imitation oil paintings is given by the function C(x)=0.1x2-3.5x+500 where x increases.
Formula Formula d d x f − g = d d x ( f ) − d d x ( g )
Chapter 4.2, Problem 24E
(a)
To determine
The nature of marginal cost from the following options such that daily cost to imitation oil paintings is given by the function C(x)=0.1x2−3.5x+500 dollars where x (the number of oil paintings) increases, options are given below:
(A) increases
(B) decreases
(C) increases, then decreases
(D) decreases, then increases
(b)
To determine
The nature of average cost from the following options such that daily cost to imitation oil paintings is given by the function C(x)=0.1x2−3.5x+500 dollars where x (the number of oil paintings) increases, options are given below:
(A) increases
(B) decreases
(C) increases, then decreases
(D) decreases, then increases
(c)
To determine
The relation between marginal cost and average cost when x=100 from the following options such that daily cost to imitation oil paintings is given by the function C(x)=0.1x2−3.5x+500 dollars where x (the number of oil paintings) increases: