Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 4.3, Problem 26PP
To determine

To calculate: The chemical energy converted in 10.0 min if the runner’s power is 400 W .

Expert Solution & Answer
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Answer to Problem 26PP

The chemical energy converted in 10.0 min is 240,000 J_ .

Explanation of Solution

Given data:

Power of the runner as she runs, P=400 W

Time, t=10.0 min

Formula used:

Power Equation:

  P=Et

Where P is the power in watts, E is the energy of the object in joules and t is the time in seconds in which energy is converted.

Calculation:

As per the problem,

  P=400Wt=10.0 min= (10.0 min)(60 s)=600s   [1 min=60 s]

Substitute the values of power and time in the rearranged power equation to get energy:

  P=EtE=PtE=(400 W)(600 s)E=240,000 J

Conclusion:

The chemical energy converted in 10.0 min is 240,000 J_ .

Chapter 4 Solutions

Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)

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