   Chapter 4.4, Problem 15E

Chapter
Section
Textbook Problem

# Find the general indefinite integral. ∫ 1 − sin 3 t sin 2 t d t

To determine

To find:

1-sin3tsin2t dt

Explanation

1)  Concept:

Apply the formula of indefinite integral and simplify.

2) Formula:

cosec2θ dθ= -cotθ+C

sinθ dθ= -cosθ+C

1sin2θ=cosec2θ

3) Calculation:

Consider,

1-sin3tsin2t dt

After separating the denominator,

1-sin3tsin2t dt=

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