   Chapter 4.4, Problem 53E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Solving Exponential and Logarithmic Equations In Exercises 47–68, solve for x or t. See Examples 5 and 6. 4 e 2 x − 1 − 1 = 5

To determine

To calculate: The value of x for the equation 4e2x11=5.

Explanation

Given Information:

The provided equation is 4e2x11=5.

Formula used:

The inverse property of logarithms for the expression, lnex is lnex=x.

The property of logarithms for the expression ln(xy) is ln(xy)=lnxlny where x and y are real numbers and greater than 0.

Calculation:

Consider the equation, 4e2x11=5.

Add 1 on both sides to the provided equation,

4e2x11+1=5+14e2x1=6

Now, divide both sides by 4 as,

4e2x14=64e2x1=32

Take natural loga

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