   Chapter 4.5, Problem 4.6CYU

Chapter
Section
Textbook Problem

Sodium bicarbonate, NaHCO3, is used in baking powder formulations and in the manufacture of plastics and ceramics, among other things. If 26.3 g of the compound is dissolved in enough water to make 200. mL of solution, what is the concentration of NaHCO3? What are the concentrations of the ions in solution?

Interpretation Introduction

Interpretation:

The molar concentration of NaHCO3 and molar concentration of ions produced from NaHCO3 solution should be determined.

Concept introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one liter of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
• Amount of substance (mol) can be determined by using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Concentrationofsubstance=Amountof substancevolumeofthesubstance
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Amount of NaHCO3 (in mol) can be calculated as follows,

26.3gNa2CO3×1molofNaHCO384.01gNaHCO3=0.3131molNaHCO3

From the above calculated value it is possible to find the concentration of NaHCO3.

ConcentrationofNaHCO3=0.3131molNaHCO30.200L=1

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