Chapter 4.5, Problem 47PS

Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728

Chapter
Section

Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728
Textbook Problem

For Problems 11-52, perform the indicated divisions. (Objective 1) ( x 5 − 1 ) ÷ ( x − 1 )

To determine

To Find:

The value of the polynomials by performing the indicated division by binomials.

Explanation

Division of a polynomial by binomial is done by using the long-division method.

In this method to find the first term of the quotient, divide the first term of the dividend by the first term of the divisor.

Multiply the divisor with the term obtained by dividing the first term of the dividend with the first term of the quotient.

The product obtained is subtracted from the dividend.

Repeat the same process to divide the other terms of the dividend.

Calculation:

Consider the expression (x5âˆ’1)Ã·(xâˆ’1).

The following steps are used to solve the division problem.

First multiply the divisor by x4 and write the product x5âˆ’x4Â  under the dividend and subtract.

The value obtained is equal to x4.

Now multiply the divisor by x3 and write the product x4âˆ’x3 under the dividend and

Subtract.

The value obtained is equal to Â x3.

Now multiply the divisor by x2 and write the product x3âˆ’x2 under the dividend and

Subtract.

The value obtained is equal to x2.

Now multiply the divisor by x and write the product x2âˆ’x under the dividend and

Subtract.

The value obtained is equal to x.

Now multiply the divisor by 1 and write the product xÂ âˆ’1 under the dividend and simplify.

By using the long division it is written as follows,

xâˆ’1x4+x3+x2+x+1x5+0x4+0x3+0x2+0xâˆ’1Â Â Â Â Â Â Â Â Â x5âˆ’x4Â Â Â Â Â Â Â Â Â Â Â Â Â Â _Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x4Â +0x3Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x4âˆ’x3Â Â Â Â Â Â Â Â Â Â Â _Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x3+0x2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x3âˆ’x2Â Â Â Â Â Â Â Â Â Â Â Â Â _Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x2+0xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â

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