Chapter 4.6, Problem 47PS

### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728

Chapter
Section

### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728
Textbook Problem

# For Problems 45-56, set up an algebraic equation and solve each problem. (Objective 3)One angle of a triangle has a measure of 60 0 , and the measures of the other two angles are in the ratio of 2 to 3. Find the measures of the other two angles.

To determine

To Find:

The measures of the other two angles of a given triangle.

Explanation

Approach:

The comparison of the two numbers by division, we can write in the form of ratio aÂ toÂ b as ab.The statement of equality between two ratio is known as proportion. Therefore if abÂ andÂ pq are two equal ratios, the proportion ratio can be form abâ€‰=â€‰pqâ€‰(bâ‰ 0,qâ‰ 0).

This property can be solve as follows.

abâ€‰=â€‰pq,Â (bâ‰ 0,qâ‰ 0)

Multiply bq on both side.

bq(ab)â€‰=â€‰bq(pq)qa=bp

Calculation:

The sum of all three angles of the triangle is 1800, so as given in problem one angle is 600 therefore the sum of other two angles become (1800âˆ’600=1200)

Consider one angle is d then the other angle will become (1200âˆ’d)

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