   Chapter 4.6, Problem 47PS

Chapter
Section
Textbook Problem

For Problems 45-56, set up an algebraic equation and solve each problem. (Objective 3)One angle of a triangle has a measure of 60 0 , and the measures of the other two angles are in the ratio of 2 to 3. Find the measures of the other two angles.

To determine

To Find:

The measures of the other two angles of a given triangle.

Explanation

Approach:

The comparison of the two numbers by division, we can write in the form of ratio a to b as ab.The statement of equality between two ratio is known as proportion. Therefore if ab and pq are two equal ratios, the proportion ratio can be form ab=pq(b0,q0).

This property can be solve as follows.

ab=pq, (b0,q0)

Multiply bq on both side.

bq(ab)=bq(pq)qa=bp

Calculation:

The sum of all three angles of the triangle is 1800, so as given in problem one angle is 600 therefore the sum of other two angles become (1800600=1200)

Consider one angle is d then the other angle will become (1200d)

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