   Chapter 4.6, Problem 4.9QQ

Chapter
Section
Textbook Problem

For the woman being pulled forward on the toboggan in Figure 4.33, is the magnitude of the normal force exerted by the ground on the toboggan (a) equal to the total weight of the woman plus the toboggan, (b) greater than the total weight, (c) less than the total weight, or (d) possibly greater than or less than the total weight, depending on the size of the weight relative to the tension in the rope?

To determine
The magnitude of force exerted by the ground on the toboggan.

Explanation

The schematic diagram for the women being pulled on the toboggan is,

• T is the tension on the rope.
• W is the total weight of the woman and toboggan.
• N is the normal force.
• θ is the angle at which rope is inclined to the horizon.

From the diagram, the formula for the normal force is given by,

N=WTsinθ

Conclusion:

The rope is inclined at an angle with respect to the horizon. There exists a vertical component of tension along the direction of the normal force. Therefore, the normal force is equal to the total weight minus the vertical component

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

After about 50 years of age, bones begin to lose dens.

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What is the plasma membrane, and what are its main functions?

Biology: The Dynamic Science (MindTap Course List)

Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.

Physics for Scientists and Engineers, Technology Update (No access codes included) 