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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

For the woman being pulled forward on the toboggan in Figure 4.33, is the magnitude of the normal force exerted by the ground on the toboggan (a) equal to the total weight of the woman plus the toboggan, (b) greater than the total weight, (c) less than the total weight, or (d) possibly greater than or less than the total weight, depending on the size of the weight relative to the tension in the rope?

To determine
The magnitude of force exerted by the ground on the toboggan.

Explanation

The schematic diagram for the women being pulled on the toboggan is,

  • T is the tension on the rope.
  • W is the total weight of the woman and toboggan.
  • N is the normal force.
  • θ is the angle at which rope is inclined to the horizon.

From the diagram, the formula for the normal force is given by,

N=WTsinθ

Conclusion:

The rope is inclined at an angle with respect to the horizon. There exists a vertical component of tension along the direction of the normal force. Therefore, the normal force is equal to the total weight minus the vertical component

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