   Chapter 4.6, Problem 4SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 1-4, solve the equation for k. 22 = 32 e − 0.02 k

To determine

To calculate: The value of k in the equation 22=32e0.02k.

Explanation

Given Information:

The provided equation is 22=32e0.02k.

Formula used:

If f(x)=ex is a function then the natural logarithm of the function that is f(x)=lnex is given by the inverse property that is,

lnex=x

If the function is f(x)=lnab, then the property of natural logarithm is given by.

lnab=lnalnb

Calculation:

Consider the equation, 22=32e0.02k

Divide both sides by 32.

2232=3232e0.02k1116=e0.02k

Take natural logarithm each side

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