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Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728

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BuyFindarrow_forward

Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
ISBN: 9781285195728
Textbook Problem

For Problem 1-30, solve each equation. (Objective 1)

n n + 3 + 1 n 4 = 11 n n 2 n 12

To determine

To solve:

The equation nn+31n4=11nn2n12.

Explanation

Approach:

Rational expression, a quotient obtained by division of two polynomials in form of p(x,y)q(x,y) where p(x,y) and q(x,y) are polynomials in such a way that the variables x, y do not assume values such that q(x,y)=0

If ab and cd are rational, then addition or subtraction of rational formed by making the denominator equal using LCD and perform the operation on the numerators as follows:

ab+cd=abdd+cdbb=adbd+cbbd=ad+cbbd

And,

abcd=abddcdbb=adbdcbbd=adcbbd

Same algebra is for rational expression.

Calculation:

The given rational expression is nn+31n4=11nn2n12

Factorize each term of the equation,

nn+31n4=11nn24n+3n12

Restriction on the equation is that n4andn3,

The lowest common denominator of the given equation is (n4)(n+3)

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