   # How is the absorbance ( A ) of a solution affected if a solution is diluted to twice the initial volume? (a) A is doubled. (b) A is reduced to half the original value. (c) A is not changed. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4.8, Problem 1RC
Textbook Problem
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## How is the absorbance (A) of a solution affected if a solution is diluted to twice the initial volume? (a) A is doubled. (b) A is reduced to half the original value. (c) A is not changed.

Interpretation Introduction

Interpretation:

It should be determined that how the absorbance (A) of a solution affected if a solution is diluted to twice the initial volume.

Concept introduction:

• Absorbance (A): it is the negative logarithm of transmittance of the sample taken. And its value increases as the concentration increases.

Absorbance=-logT=-logPP0

T is the transmittance and it is the ratio of the amount of light transmitted by or passing through the sample (P) relative to the light that initially fell on the sample.

Transmittance(T)=PP0=IntencityoftransmittedlightIntencityofincidentlight

### Explanation of Solution

Given,

The solution is diluted to twice the initial volume.

If the volume increases then the concentration of the solution is decreases.

Absorbance (A) is the negative logarithm of transmittance of the sample taken. And its value increases as the concentration increases.

Absorbance=-logT=-logPP0

Here concentration is reduced to twice therefore the Absorbance (A) is reduced to half the original value.

Thus,

Option (b) is the correct answer.

Absorbance (A) is reduced to half the original value (option b) when the solution is diluted to twice the initial volume

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