   Chapter 4.CR, Problem 50CR

Chapter
Section
Textbook Problem

Mark can overhaul an engine in 20 hours, and Phil can do the same job by himself in 30 hours. If they both work together for a time and then mark finishes the job by himself in 5 hours, how long did they work together?

To determine

To Find:

The time Mark and Phil work together.

Explanation

Approach:

The rate of work in uniform-work rate problems can be express as.

R=QT

Here, rate of work is R, work done quantity is Q and time taken to do the Q quantity work is T.

Calculation:

Consider the time Mark and Phil work together is t and quantity of work is 1unit.

The quantity of work done by Mark in 5hours.

Work done by Mark alone=(120)×5=14

Remaining work,

Remainingwork=totalworkcompletedworkbymark=114=34

The remaining work will be equal to sum of work done by both when they work together for the same time

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