   # Phosphorus can be prepared from calcium phosphate by the following reaction: 2 Ca 3 ( PO 4 ) 2 ( s ) + 6 SiO 2 ( s ) + 10 C ( s ) → 6 CaSiO 3 ( s ) + P 4 ( s ) + 10 CO ( g ) Phosphorite is a mineral that contains Ca 3 (PO 4 ) 2 plus other non-phosphorus-containing compounds. What is the maximum amount of P 4 that can be produced from 1.0 kg of phosphorite if the phorphorite sample is 75% Ca 3 (PO 4 ) 2 by mass? Assume an excess of the other reactants. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 112E
Textbook Problem
33 views

## Phosphorus can be prepared from calcium phosphate by the following reaction: 2 Ca 3 ( PO 4 ) 2 ( s )   +   6 SiO 2 ( s )   +   10 C ( s ) → 6 CaSiO 3 ( s )   +  P 4 ( s )   +   10 CO ( g ) Phosphorite is a mineral that contains Ca3(PO4)2plus other non-phosphorus-containing compounds. What is the maximum amount of P4 that can be produced from 1.0 kg of phosphorite if the phorphorite sample is 75% Ca3(PO4)2 by mass? Assume an excess of the other reactants.

Interpretation Introduction

Interpretation: The maximum amount of P4 that can be produced from 1.0kg of phosphorite is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The maximum amount of P4 that can be made using 1.0kg of phosphorite.

### Explanation of Solution

Given

The stated chemical equation is,

2Ca3(PO4)2(s)+6SiO2(s)+10C(s)6CaSiO3(s)+P4(s)+10CO(g)

The given mass of phosphorite is 1.0kg(1000g) .

The mass of Ca3(PO4)2 is 75% of the mass of phosphorite.

Therefore, the mass of Ca3(PO4)2 =(75100×1000)g=750g

Molar mass of Ca3(PO4)2 =3Ca+2P+8O=((3×40)+(2×31)+(8×16))g/mol=310g/mol

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=GivenmassofthesubstanceAtomicmassofthesubstance

Substitute the value of the given mass and the atomic mass of Ca3(PO4)2 in the above expression.

NumberofmolesofCa3(PO4)2=750g310g/mol=2

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Magnesium a. assists in the operation of enzymes. b. is needed for the release and use of energy. c. is critica...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

a 5.74 cg to g, b 1.41 kg to g, c 4.54 x 108 cg to mg

Introductory Chemistry: An Active Learning Approach

Is there really any such thing as a true tidal wave?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin

The magnetic field created by a large current passing through plasma (ionized gas) can force current-carrying p...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Why cant stars generate energy from iron fusion?

Foundations of Astronomy (MindTap Course List) 