   # A piece of gold (10.0 g, C Au = 0.129 J/g · K) is heated to 100.0 °C. A piece of copper (also 10.0 g, C Cu = 0.385 J/g · K) is chilled in an ice bath to 0 °C. Both pieces of metal are placed in a beaker containing 150. g H 2 O at 20 °C. Will the temperature of the water be greater than or less than 20 °C when thermal equilibrium is reached? Calculate the final temperature. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 5, Problem 114SCQ
Textbook Problem
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## A piece of gold (10.0 g, CAu = 0.129 J/g · K) is heated to 100.0 °C. A piece of copper (also 10.0 g, CCu = 0.385 J/g · K) is chilled in an ice bath to 0 °C. Both pieces of metal are placed in a beaker containing 150. g H2O at 20 °C. Will the temperature of the water be greater than or less than 20 °C when thermal equilibrium is reached? Calculate the final temperature.

Interpretation Introduction

Interpretation:

At thermal equilibrium final temperature of the water has to be determined.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1k.Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat capacity,ΔT= change in temperature.

### Explanation of Solution

Assume qAu+qCu=qwater

[10g×0.129J/gK(T-373K)]+[10g×0.385J/gK(T-273K)]=

150g×4.184J/gK(T-293K)

1.29T-481

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