   # A sample of LSD (D-lysergic acid diethylamide, C 24 H 30 N 3 O) is added to some table salt (sodium chloride) to form a mixture. Given that a 1.00-g sample of the mixture undergoes combustion to produce 1.20 g of CO 2 , what is the mass percent of LSD in the mixture? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 143AE
Textbook Problem
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## A sample of LSD (D-lysergic acid diethylamide, C24H30N3O) is added to some table salt (sodium chloride) to form a mixture. Given that a 1.00-g sample of the mixture undergoes combustion to produce 1.20 g of CO2, what is the mass percent of LSD in the mixture?

Interpretation Introduction

Interpretation: A sample of is added to some amount of sodium chloride to form a mixture. The mass percent of LSD in the mixture is to be calculated.

Concept introduction: The mass of a substance is calculated by the formula,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The mass percent of LSD in the mixture.

### Explanation of Solution

Given

The combustion of 1g of the given mixture produces 1.20g of carbon dioxide (CO2) .

The reaction that occurs on the combustion of LSD (C24H30N3O) is,

C24H30N3O+excessO224CO2+otherproducts

The molar mass of CO2 =C+2O=(12+(2×16))g/mol=44g/mol

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=GivenmassofthesubstanceMolarmassofthesubstance

Substitute the value of the given mass and the molar mass of CO2 in the above expression.

NumberofmolesofCO2=1.20g44g/mol=0.0272mol

24mol of CO2 is produced from C24H30N3O =1mol

1mol of CO2 is produced from C24H30N3O =(124)mol

0.0272mol of CO2 is produced from C24H30N3O =(1×0.027224)mol=0

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