   Chapter 5, Problem 14P

Chapter
Section
Textbook Problem

A 62.0-kg cheetah accelerates from rest to its top speed of 32.0 m/s. (a) How much net work is required for the cheetah to reach its top speed? (b) One food Caloric equals 4 186 J. How many Calories of net work are required for the cheetah to reach its top speed? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the cheetah’s body.

(a)

To determine
The net work done required for the cheetah to reach its top speed.

Explanation

Given Info:

The mass of cheetah is 62.0kg .

The top speed of cheetah is 32.0m/s .

According to Work- Energy theorem, the net work done on an object is equal to the change in internal energy of the object. Thus,

Wnet=KEfKEi

• KEf is the final kinetic energy
• KEi is the initial kinetic energy

Since, the cheetah is starting the run from rest, the initial kinetic energy of the cheetah is zero.

So,

Wnet=KEf=12mvf2

• m is the mass of cheetah
• vf is the final velocity of the cheetah

Substitute 62

(b)

To determine
How many calories of net work done are required for the cheetah to reach its top speed.

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