Basic Engineering Circuit Analysis
11th Edition
ISBN: 9781118539293
Author: J. David Irwin, R. Mark Nelms
Publisher: WILEY

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Textbook Question
Chapter 5, Problem 1P

Find I o in the network in Fig. P5.1 using linearity and the assumption that I o = 1 mA .

To determine

The value of current Io using linearity property.

The value of Iois0.5mA.

Explanation of Solution

Given:

A circuit is given with an assumption that Io = 1mA.

Calculations:

Mark the node with voltage V and current in all branches.

As given Io = 1mA passing through the 6kΩ resistor, the voltage across it will be 6V (product of current and resistance).

The value of I3 -

I3=62=3mA

From circuit, I2 is sum of IoandI3

I2 =1+3=4 mA

Applying KVL,

V=3I2+6=3×4+6V=18V

Therefore, I1 -

I1=V6=186I1=3mA

Where

IS=I1+I2=3+4IS=7mA

Let the voltage source be denoted by VS, then apply the KVL in the circuit-

VS=2IS+V=2×7+18VS=32V

Therefore if

VS=32VIo=1mAThenVS=64VIo=2mA

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