   Chapter 5, Problem 1P

Chapter
Section
Textbook Problem

A weight lifter lifts a 350-N set of weights from ground level to a position over his head, a vertical distance of 2.00 m. How much work does the weight lifter do, assuming he moves the weights at constant speed?

To determine
The total work done by the weightlifter.

Explanation

Given Info:

The weight that the weightlifter lifted is 350N .

The vertical distance that the weightlifter lifts the weight is 2.00m

When the weightlifter lifts the weight with a constant velocity, the net force on the weights will be zero. Hence, the only the force excreted on the weights is upward.

So, the angle between the force vector and the displacement vector is zero.

Formula to calculate the work done is,

W=(Fcosθ)d

• θ is the angle between the force vector and the displacement vector
• F is the force
• d is the magnitude of displacement

Substitute 350N for F, zero θ and 2

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