Chapter 5, Problem 1P

To determine

To plot:

The function $f\left(x\right)=x^2-10\sqrt{x}+2$ for $0\le x\le 5$ by using $\text{plot}$ command.

Answer to Problem 1P

Solution:

The plot of the function $f\left(x\right)=x^2-10\sqrt{x}+2$ for $0\le x\le 5$ is stated as follows.

Explanation of Solution

The given function is,

$f\left(x\right)=x^2-10\sqrt{x}+2$

The range of function is $0\le x\le 5$.

Substitute $x=0$ in the above equation.

$\begin{array}{c}f\left(x\right)=x^2-10\sqrt{x}+2\\ ={\left(0\right)}^2-10\sqrt{\left(0\right)}+2\\ =+2\end{array}$ <

Substitute $x=5$ in the above equation.

$\begin{array}{c}f\left(x\right)=x^2-10\sqrt{x}+2\\ ={\left(5\right)}^2-10\sqrt{\left(5\right)}+2\\ =4.6393\end{array}$

The value of $f\left(x\right)$ lies from $2\le f(x)\le 4.6393$.

Write the MATLAB script to plot the function $f\left(x\right)=x^2-10\sqrt{x}+2$ for $0\le x\le 5$.

MATLAB Code:

x = [0:0.01:5];

% Define the vector x.

y = x.^2-(10*sqrt(x))+2;

% Define the function y.

plot(x,y,'-g')

Save the MATLAB script with name, Chapter5_56830_5_1P.m in the current folder. Execute the script by typing the script name at the command window to get the plot of the function $f\left(x\right)=x^2-10\sqrt{x}+2$ for $0\le x\le 5$.

Result:



Conclusion:

The plot of the function $f\left(x\right)=x^2-10\sqrt{x}+2$ for $0\le x\le 5$ is stated above.