   Chapter 5, Problem 21P

Chapter
Section
Textbook Problem

A block of mass 3.00 kg is placed against a horizontal spring of constant k = 875 N/m and pushed so the spring compresses by 0.070 0 m. (a) What is the elastic potential energy of the block-spring system? (b) If the block is now released and the surface is frictionless, calculate the block’s speed after leaving the spring.

(a)

To determine
The elastic potential energy of the block-spring system.

Explanation

Given Info:

The mass of the block is 3.00kg .

The spring constant is 875N/m .

The length by which the spring is compressed is 0.070m .

Formula to calculate the elastic potential energy is,

PEs=12kx2

• k is the spring constant
• x is the length by which the spring is compressed

Substitute 875N/m for k and 0

(b)

To determine
The speed of the block after leaving the spring.

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