   Chapter 5, Problem 22RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Applying the General Power Rule In Exercises 21–32, find the indefinite integral. Check your result by differentiating. ∫ ( x − 6 ) 4 / 3   d x

To determine

To calculate: The indefinite integral (x6)4/3dx.

Explanation

Given Information:

The provided indefinite integral is (x6)4/3dx.

Formula used:

The power rule of integrals:

undu=un+1n+1+C (n1)

The power rule of differentiation:

ddxun=nun1+C

Calculation:

Consider the indefinite integral:

(x6)4/3dx

Let u=x6, then derivative will be,

du=d(x6)=dx

Substitute du for dx and u for x6 in provided integration.

(x6)3dx=u43du

Now apply, the power rule of integrals:

u4/3du=

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