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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 5, Problem 24E
Textbook Problem
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Determine whether each compound is ionic or molecular and draw an appropriate Lewis structure:

a . K 2 O b . CHClO  ( carbon is the central atom ) c . SrS d . CH 3 Cl  ( carbon is the central atom )

Interpretation Introduction

Interpretation:

Whether each of the given compounds is ionic or molecular is to be determined. The Lewis structures for each of the given compounds are to be drawn.

Concept Introduction:

The steps for drawing the Lewis structures of ionic compounds are as follows:

The Lewis structures of elements are combined to form the Lewis structures of compounds.

The dots are moved from the Lewis structure of the metal to the Lewis structure of the non-metal.

The metal becomes a cation and the non-metal becomes an anion.

According to the Lewis theory, in covalent bonding, atoms share their electrons. The steps for drawing a covalent Lewis structure are as follows:

Write the skeletal structure of the molecule.

Add the number of valence electrons of each atom in the molecule in order to calculate the total number of electrons present in the molecule.

Place the electrons by dots to complete the octets of the atoms.

If the central atom has not obtained an octet, then its multiple bonds can be formed.

Explanation of Solution

a) K2O

K2O is an ionic compound as it is made up of a metal and a non-metal. In this compound, K is the metal, whereas O is the non-metal.

Potassium (K) and oxygen (O) have the following Lewis structures:

Potassium loses its valence electron to obtain an octet while oxygen needs two electrons to complete its octet. Thus, two potassium atoms are required per oxygen atom.

Hence, the Lewis structure of K2O is as follows:

b) CHClO (C is the central atom)

CHClO is a covalent compound as it contains carbon and hydrogen atoms.

Carbon is the central atom, and chlorine, hydrogen, and oxygen atoms are arranged around it. Thus, the skeletal structure of the compound is:

H     C     Cl         O

Now, calculate the total number of electrons for the molecule.

Total electrons = valence electrons for Cl + valence electrons for C + valence electrons for O+ valence electron for H= 7+ 4 + 6+1= 18

Place the electrons as dots to give octet to each of the atoms in the molecule. One double bond is formed between carbon and oxygen, so that carbon obtains its octet.

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Chapter 5 Solutions

Chemistry In Focus
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