Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 5, Problem 26PDQ
In a certain plant, fruit is either red or yellow, and fruit shape is either oval or long. Red and oval are the dominant traits. Two plants, both heterozygous for these traits, were testcrossed, with the following results.
Determine the location of the genes relative to one another and the genotypes of the two parental plants.
Expert Solution & Answer
Learn your wayIncludes step-by-step video
schedule06:55
Students have asked these similar questions
In a certain plant, fruit is either red or yellow, and fruit shape is either oval or long. Red and oval are the dominant traits. Two plants, both heterozygous for these traits, were testcrossed, with the following results. Progeny Phenotype Plant A Plant B red, long 46 4 yellow, oval 44 6 red, oval 5 43 yellow, long 5 47 100 100 Determine the location of the genes relative to one another and the genotypes of the two parental plants.
Assume that three loci, each with two alleles (A and a, B and b, C and c), determine the difference in height between two homozygous strains of a plant. These genes are additive and equal in their effects on plant height. One strain (aa bb cc) is 10 cm in height. The other strain (AA BB CC) is 22 cm in height. The two strains are crossed, and the resulting F1 are interbred to produce F2 progeny. Give the phenotypes and the expected proportions of the F2 progeny.
The following results were obtained from a dihybrid cross between two pea plants:
315 plants with round seeds and yellow flowers
101 plants with wrinkled seeds and yellow flowers
108 plants with round seeds and white flowers
32 plants with wrinkled seeds and white flowers
Assume that round seeds and yellow flowers are dominant and both parent plants were heterozygous for both traits.
Chapter 5 Solutions
Concepts of Genetics (11th Edition)
Ch. 5 - In a family with one autistic child the risk for...Ch. 5 - Given that the prenatal test can provide only a...Ch. 5 - Prob. 3CSCh. 5 - Prob. 4CSCh. 5 - Consider two hypothetical recessive autosomal...Ch. 5 - With two pairs of genes involved (P/p and Z/z), a...Ch. 5 - In Drosophila, a heterozygous female for the...Ch. 5 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 5 - Review the Chapter Concepts list on page 94. Most...Ch. 5 - Describe the cytological observation that suggests...
Ch. 5 - Why does more crossing over occur between two...Ch. 5 - Explain why a 50 percent recovery of...Ch. 5 - Why are double-crossover events expected less...Ch. 5 - What is the proposed basis for positive...Ch. 5 - What two essential criteria must be met in order...Ch. 5 - The genes dumpy (dp), clot (cl), and apterous (ap)...Ch. 5 - Colored aleurone in the kernels of com is due to...Ch. 5 - In the cross shown here, involving two linked...Ch. 5 - In a series of two-point mapping crosses involving...Ch. 5 - Two different female Drosophila were isolated,...Ch. 5 - In Drosophila, a cross was made between femalesall...Ch. 5 - Another cross in Drosophila involved the...Ch. 5 - In Drosophila, Dichaete (D) is a mutation on...Ch. 5 - Drosophila females homozygous for the third...Ch. 5 - In Drosophila, two mutations, Stubble (Sb) and...Ch. 5 - If the cross described in Problem 18 were made,...Ch. 5 - Are mitotic recombinations and sister chromatid...Ch. 5 - What possible conclusions can be drawn from the...Ch. 5 - An organism of the genotype AaBbCc was testcrossed...Ch. 5 - Based on our discussion of the potential...Ch. 5 - Traditional gene mapping has been applied...Ch. 5 - DNA markers have greatly enhanced the mapping of...Ch. 5 - In a certain plant, fruit is either red or yellow,...Ch. 5 - Two plants in a cross were each heterozygous for...Ch. 5 - A number of humanmouse somatic cell hybrid clones...Ch. 5 - A female of genotype produces 100 meiotic tetrads....Ch. 5 - In laboratory class, a genetics student was...Ch. 5 - Drosophila melanogaster has one pair of sex...Ch. 5 - In Drosophila, a female fly is heterozygous for...Ch. 5 - The gene controlling the Xg blood group alleles...Ch. 5 - Prob. 34ESP
Additional Science Textbook Solutions
Find more solutions based on key concepts
Why are BSL-4 suits pressurized? Why not just wear tough regular suits?
Microbiology with Diseases by Body System (4th Edition)
21-Year-Old Female with Skeletal Injuries
While riding her bike to campus, 21-year-old Liliana Rose was struck...
Human Anatomy & Physiology (11th Edition)
Define histology.
Fundamentals of Anatomy & Physiology Plus Mastering A&P with eText - Access Card Package (10th Edition) (New A&P Titles by Ric Martini and Judi Nath)
Which type of cartilage is most plentiful in the adult body?
Anatomy & Physiology
1. What are the main organs of the skeletal system?
Human Anatomy & Physiology (2nd Edition)
WRITE ABOUT A THEME: ORGANIZATION Cells arc the basic units of structure and function in all organisms. A key f...
Campbell Biology (11th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A sugarcane plant with yellow pollen and wavy leaves is crossed with a plant with yellow pollen andsmooth leaves. Seed are collected and germinated. The following results are obtained in the progeny:153 yellow pollen, wavy leaves145 yellow pollen, smooth leaves48 white pollen, wavy leaves 51 white pollen, smooth leavesa. For each locus (trait), assign appropriate symbols for the alleles of the genes, indicate thedominance interaction between the two alleles, and give all possible genotypes and theirassociated phenotypes.b. Give the genotypes of the parents of this cross.c. Give the expected genotypic and phenotypic ratios of the progeny of this cross. Please use aPunnett square to visualize your cross. Thank you very much for your assistance as it is greatly appreciated, a like is guaranteed if all subquestions are answered.arrow_forwardTwo plants, both heterozygous for these traits, were testcrossed,with the following results.ProgenyPhenotype Plant A Plant Bred, long 46 4yellow, oval 44 6red, oval 5 43yellow, long 5 47100 100Determine the location of the genes relative to one anotherand the genotypes of the two parental plants.arrow_forwardIn the garden pea, yellow cotyledon color is dominant to green, and inflated pod shape is dominant to the constricted form. Considering both of these traits jointly in self-fertilized dihybrids, the progeny appeared in the following numbers: 193 green, inflated 184 yellow, constricted 556 yellow, inflated 61 green, constricted Do these genes assort independently? Support your answer using Chi-square analysis.arrow_forward
- A heterozygous plant of AaBb genotype was testcrossed and gave the following results. Phenotypes A _B_ A_bb aaB_ aabb Number 140 38 32 150 Are genes A and B independently inherited? Show the mathematical basis of your decision. If genes A and B are not independently inherited, what could be the alternative mode of inheritance?arrow_forwardYou identify a gene that determines the size of the pods of a pea plant. To study the phenotype associated with this trait, you cross a plant that is homozygous for the “long pod” allele with a pea plant that is homozygote for “short pod” allele. When measuring the length of the pods of the parents and resulting offspring, you obtain the following data: Plant Length (cm) Homozygous (“Wide” allele) 15 cm Homozygous (“Short” allele) 4 cm Resulting cross breed 9 cm What can you conclude about this phenotype/trait? Long and short alleles are codominant Wide allele shows incomplete dominance over the short allele Wide allele shows complete dominance over the short allele Short allele shows complete dominance over the long allele The wide and short genes are linkedarrow_forwardSuppose a species of tulip has three alleles for the gene that codes for flower color. The CR allele produces red tulips, the CB allele produces blue tulips, and the CW allele produces white tulips. Both CR and CB are dominant over CW, but CR and CB are incompletely dominant with each other, so CRCB heterozygotes have purple flowers. What is the expected phenotypic ratio in the offspring of the following crosses, in the order red : blue : purple : white? Enter your answers as the most simplified ratio (e.g. 1 : 2 : 1 : 1 instead of 2 : 4 : 2 : 2). Enter 0 if none of the offspring from a cross will be a particular color. CRCB × CBCW _____ red : ______blue : ______purple : ______white CRCB × CRCW - _______red : _____blue : _____purple : _____white CRCW × CBCW - _____red : _____blue : _____purple : _____white CRCB × CRCB - red : blue : purple : whitearrow_forward
- Assume that the genes for seed color and seed shape are located on the same chromosome. A plant heterozygous for both genes is testcrossed wrinkled green with the following results: green, wrinkled 645 green, round 36 yellow, wrinkled 29 yellow, round 590 What were the genotypes of the parents, and how far apart are these genes?arrow_forwardIn corn, a pair of genes determines leaf shape and another pair determines pollen shape. A ragged-leafed plant with round-pollen was crossed to a ragged-leaf plant with angular pollen, and the resultant progeny were classified as follows: 186 ragged-leaf round-pollen 174 ragged-leaf angular pollen 57 smooth-leaf round pollen 63 smooth-leaf angular-pollen provide your hypothesis of the genotypes for the two parents. According to your hypothesis, what numbers would you have expected for each of the four classes of progeny? Follow the format of the number with the phenotypes in the question above. Test your hypothesis statistically using the chi-square method and indicate whether you accept or reject your hypothesis. Show your solutions.arrow_forwardThree corn seed traits are C for red, c for white; S for plump, s for shrunken; W for normal, w for waxy. Use the data from the testcross to map the distances and order of these three loci. Show calculations and illustrate the gene map. (Hint: drawing out the chromosomes and gametes will help.) Parents: CCssWW (CsW/CsW) X ccSSww (cSw/cSw) Trihybrid: CcSsWw (CsW/cSw) X ccssww (csw/csw) Test cross offspring Seed trait Gamete from trihybrid Number Red, shrunken, normal CsW 2777 White, plump, waxy cSw 2708 R ed, plump, waxy CSw 116 White, shrunken, normal csW 123 Red, shrunken, waxy Csw 643 White, plump, normal cSW 626 Red, plump, normal CSW 4 White, shrunken, waxy csw 3 Total number of progeny: 7000arrow_forward
- A diploid plant has red flowers, heavy seeds and large leaves. The plant is a heterozygous for the following three genes:flower color (gene “F”),seed weight (gene “S”),and leaf size (gene “L”). This plant is testcrossed to a plant, which has white flowers, light seeds, and small leaves, the progeny of the testcross is as follows: 222 Red, heavy, large 228 White, light, small 224 Red, heavy, small 226 White, light, large 24 Red, light, large 26 White, heavy, small 25 White, heavy, large 25 Red, light, small Based on this results, which of the following statement is correct? Question 9 options: All three genes are on different chromosomes. Genes S and L are linked, while F assorts independently. Genes F and S are linked, while L assorts independently. Genes F and L are linked, while S assorts independently.arrow_forwardFigure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?arrow_forwardHemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax CollegeHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
- Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY