   Chapter 5, Problem 26RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Applying the General Power Rule In Exercises 21–32, find the indefinite integral. Check your result by differentiating. ∫ ( 6 x − 2 ) 4   d x

To determine

To calculate: The indefinite integral (6x2)4dx.

Explanation

Given Information:

The provided indefinite integral is (6x2)4dx.

Formula used:

The power rule of integrals:

undu=un+1n+1+C (n1)

The power rule of differentiation:

ddxun=nun1+C

Calculation:

Consider the indefinite integral:

(6x2)4dx

Let u=6x2, then derivative will be,

du=d(6x2)=6dx

Rewrite integration as,

(6x2)4dx=16(6x2)46dx

Substitute du for 6dx and u for 6x2 in provided integration

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