Concept explainers
In a diploid species of plant, the genes for plant height and fruit shape are syntenic and separated by
A plant with the genotype
Give the same information for a plant with the genotype
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Chapter 5 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
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- In tomato plants, tall vine (D) is dominant over dwarf vine (d) and round fruit (O) is dominant over oval-shaped fruit (o). Two tall, round-fruit shape plants (plants 1 and 2) are crossed with dwarf, oval-shape fruit plants. The results are as follows: i) Why is there a difference in the proportionate number of plants in each phenotypic class of the offspring resulting from test crosses of plants 1 and 2? (ii) Calculate the recombination frequency between the genes D/d and O/o in tomatoes. (iii) Draw a chromosome map for these genes. (Use underscore (_) to draw the line for the map)arrow_forwardA cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 494 w + + 394 + + ct 28 w y + 35 + y + 105 w + ct 101 w y ct 5 + + + 3arrow_forwardCross Cross A Cross A Cross B Cross B Phenotype F1 generation F2 generation F1 generation F2 generation Male red eyes 132 150 0 99 Female red eyes 135 295 110 101 Male white eyes 0 147 105 93 Female white eyes 0 0 0 95 Using “+” to indicate the wildtype red-eyed allele and “w” to indicate the mutant white-eyed allele, state the genotypes of the following: Wildtype red-eyed and white-eyed parental flies from cross A and cross B. Males and females from the F1 generation flies from cross A and cross B Males and females, F2 generation flies from cross A and cross B.arrow_forward
- In corn, a colored aleurone is due to the presence of an R allele; r/r is colorless. Another gene controls the color of the plant, with g/g being yellow and G_being green. A plant of unknown genotype is test-crossed, and the following progeny plants were obtained. Colored green 89 Colored yellow 13 Colorless green 9 Colorless yellow 92 What was the phenotype and genotype of the plant used for the test cross? A. Colorless green - rG/rg B. Colorless yellow - rg/rg C. Colored yellow - Rg/rg D. Colored green - RG/rgarrow_forwardIn a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. Calculate the recombination frequency between each pair of genesarrow_forwardHemophilia and color blindness are both recessive conditions caused by genes on the X chromosome . To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness , their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters’ sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia 24 have neither of the traits , 1 has color blindness only and 1 has hemophilia only . how many centimorgans seperate the hemophilia locus from the locus of the color blindness.arrow_forward
- Match the term with the correct definition or example Product of a cross between true breeding plants that make yellow peas and true breeding plants that make green peas. A description of the alleles present in an individual at one or more loci. Example: MM or Mm or mm. Example: 11q1. 4-q2. 1", meaning it is on the long arm of chromosome 11, somewhere in the range from sub-band 4 of region 1 to sub-band 1 of region 2. Under a microscope, these look exactly the same. The centromere, banding, long arm, short arm, overall length, gene locations, and order of genes are exactly the same. However, nucleotide sequences in genes on the two chromosomes can differ. the unit of heredity, the sequence of nucleotides in the exon regions specifies the sequence of amino acids in a particular polypeptide Brown allele in eye color Red eye in fruit flies Ability to synthesize alcohol dehydrogenase in fruit flies…arrow_forwardA series of three-point testcrosses is made to determine the genetic map order of seven linked allele pairs: A/a, B/b, G/g, H/h, Q/q, R/r, and Y/y.From each cross between a triply heterozygous parent listed below, two recombinant classes were noticed as the least frequent among all 8 progeny classes, and are listed at the right in the table. A. For each testcross write the genotype of the F1 heterozygous parent. F1 Parental Phenotype Least frequent F2 Phenotype 1.AHB&ahb AHb & ahB 2.RYh&ryH RYH & ryh 3.BhY&bHy Bhy & bHY 4.qYB&Qyb qYb & QyB 5.AbQ&aBq Abq & aBQ 6.ghR&GHr ghr & GHR B. Write the unified map order of these genes, showing your reasoning.arrow_forwardCross 1 AaBb x AaBb Cross 2 AaBbCc x AaBbCc a) Please use a branching diagram to find the genotypic ratios of the offspring of cross 1 illustrated above and complete with the resulting genotypes and ratios. How many different genotypes are there in the offspring of this cross? [ ] Genotype ratios for the offspring of Cross 1 (please indicate both the ratio and the genotype for each one: e.g.: 3AABB:1aabb, etc): [ ] b) Please use a branching diagram to find the phenotypic ratios of the offspring of cross 2 and complete below the resulting phenotypes and ratios. How many different phenotypes are in the offspring of this cross [ ] Phenotype ratios for the offspring of Cross 2 (please indicate both the ratio and the phenotype for each one using D and R for dominant and recessive phenotypes respectively, for example 1DDD:2DRR, etc.): [ ] c) What mathematical operation are you using to calculate the ratios for multiple genes and what…arrow_forward
- Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY. (A) For a standard monohybrid cross (Ss ´ Ss), what proportion of the offspring will have the genotype ss? (Express the proportion as a simple fraction) (B) For the following cross (SsXX ´ SsXY), what proportion of the offspring will have the genotype Ss? (Express the proportion as a simple fraction) (C) What proportion will have the genotype XX? (Express the proportion as a simple fraction) (D) What proportion will have the genotype SsXX? (Express the proportion as a simple fraction)SHOW YOUR WORKarrow_forwardHemophilia and colorblindness are both recessive conditions caused by mutations in genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with the normal alleles and one chromosome with two mutant alleles), and the daughter’s sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has colorblindness only, and one has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness? Show your analysisarrow_forwardIn corn, a colored aleurone is due to the presence of an R allele; r/r is colorless. Another gene controls the color of the plant, with g/g being yellow and G_being green. A plant of unknown genotype is test-crossed, and the following progeny plants were obtained. Colored green 89 Colored yellow 13 Colorless green 9 Colorless yellow 92 What is the recombination frequency between the R locus and the G locus? A. 45.6% B. 9.85% C. 91.15% D. 4.93% E. 6.4%arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning