   Chapter 5, Problem 47PS

Chapter
Section
Textbook Problem

An “ice calorimeter” can be used to determine the specific heat capacity of a metal. A piece of hot metal is dropped onto a weighed quantity of ice. The energy transferred from the metal to the ice can be determined from the amount of ice melted. Suppose you heated a 50.0-g piece of silver to 99.8 °C and then dropped it onto ice. When the metal’s temperature had dropped to 0.0 °C. it is found that 3.54 g of ice had melted. What is the specific heat capacity of silver?

Interpretation Introduction

Interpretation:

The specific heat capacity of silver has to be calculated.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1K.Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat

Capacity,ΔT= change in temperature.

Explanation

Given,

Heat absorbed =333J1g-ice×3.54g=1180J

Heat is released by the metal=-1180J

Rearrange and substitute the values in q=C×m×ΔT, as

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