   # The Freons are a class of compounds containing carbon, chlorine, and fluorine. While they have many valuable uses, they have been shown to be responsible for depletion of the ozone in the upper atmosphere. In 1991, two replacement compounds for Freons went into production: HFC- 134a (CH 2 FCF 3 ) and HCFC-124 (CHCLFCF 3 ) . Calculate the molar masses of these two compounds. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 50E
Textbook Problem
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## The Freons are a class of compounds containing carbon, chlorine, and fluorine. While they have many valuable uses, they have been shown to be responsible for depletion of the ozone in the upper atmosphere. In 1991, two replacement compounds for Freons went into production: HFC- 134a (CH2FCF3) and HCFC-124 (CHCLFCF3) . Calculate the molar masses of these two compounds.

Interpretation Introduction

Interpretation: The molar mass of CH2FCF3 and CHClFCF3 is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it. Also one mole of any compound is same as atomic weights.

To determine: The molar mass of CH2FCF3 and CHClFCF3 .

### Explanation of Solution

To determine: The molar mass of CH2FCF3

The atomic weight of Carbon (C) is 12.010g/mol .

The atomic weight of Hydrogen (H) is 1.0079g/mol .

The atomic weight of Chlorine (Cl) is 35.453g/mol .

The atomic weight of Fluorine (F) is 18.998g/mol .

In a compound CH2FCF3 , two Carbon atoms,. two Hydrogen atoms and four Fluorine atoms are present. Hence, atomic weight of these atoms is,

2C=12.010g/mol×2=24.02g/mol4F=18.998g/mol×4=75.992g/mol2H=1.0079g/mol×2=2.0158g/mol

The molar mass of CH2FCF3 is,

24.02g/mol+75.992g/mol+2.0158g/mol=102.0278g/mol

To determine: The molar mass of CHClFCF3

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