Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 5, Problem 5.11.2P
To determine
The W shape for the given conditions by LRFD.
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A simply supported beam subjected to a uniform service Dead load of 20kn/m (including the weight of the beam), a uniform service live load of 35kn/m. The beam is 12m long and is laterally supported at midspan, and A572 Gr. 50 steel is used. Assuming cb =1. Verify if w30x108 is adequate? Use fy=344 mpa
An A36 W14X605 simply supported steel beam with span L=13.7m carries a concentrated service liveload “PLL” at midspan. The beam is laterally supported at supports and its midspan. Consider its beam selfweight to be its service deadload, “w” (use ASEP steel manual for selfweight, w and other section properties). Calculate the maximum service PLL that the beam can carry based on deflection requirement? Use deflection limit of L/240. Express your answer in KN in 2 decimal places.
A W12x65 is to be used as a simply supported beam on a span of 20 ft with lateral support at the ends only. The beam is required to support a plastered ceiling. If the dead load is 0.20kips/ft (including beam weight), what is the maximum uniform service live load permitted on the beam, using A992 steel? What percentage increase in live load can be gained if the beam is A572 Grade 65 steel. Use AISC 360-16 specifications
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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- Use A992 steel and select a W14 shape for an axially loaded column to meet the following specifications: The length is 22 feet, both ends are pinned, and there is bracing in the weak direction at a point 10 feet from the top. The service dead load is 142 kips, and the service live load is 356 hips. a. Use LRFD. b. Use ASD.arrow_forwardIf the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same as Cb for unbraced length CB). Do not include the beam weight in the loading. a. Use the unfactored service loads. b. Use factored loads.arrow_forwardThe cantilever beam shown is aW10 × 77 of A992 steel. There is no lateral supportother than at the fixed end. Use an unbracedlength equal to the span length and determinewhether the beam is adequate. The uniform load isa service dead load that includes the beam weight,and the concentrated load is a service live load.arrow_forward
- Consider the cross section shown. All structural steel is A36. Use LRFD and ASDmethod and NSCP(AISC) specifications. For A36steel; Fy = 248 MPa; Fu = 400 MPaDETERMINE THE FOLLOWING:1. Determine the governing effective length and the governing slenderness ratio.2. Determine the design capacity of the column.3.3. Determine the maximum service live load that the column can support if the live load is twice the dead load.arrow_forwardThe beam shown below is laterally supported at the ends and 1/3 points (points 1, 2, 3, and 4). The concentrated loading shown is a service live loading. Use A992 (50-ksi) steel and selected the lightest w-shape to support the loading shown. Use the LRFD methodology. Consider the following in your design of the beam: a.) flexural (moment) capacity; b.) compact section criteria.arrow_forwardUse A992 steel and select a W shape for typical floor beam AB. Assume that the floorslab provides continuous lateral support. The maximum permissible live load deflection is L/180.The service dead loads consist of a 5-inch thick reinforced concrete floor slab (normal weightconcrete), a partition load of 20 psf, and 10 psf to account for suspended ceiling and mechanicalequipment. Don’t forget to check with self-weight. The service live load is 65 psf. You may useAISC Table 3-2 and/or Table 3-10 to check for bending and shear. Use LRFD only.arrow_forward
- Bending Strength of Compact Shapes Repeat Problem 5.5-13 for an MC18 × 51.9 (Assume that the load is applied through the shear center so that there is no torsional loading.) Use Fy = 36 ksi. (Reference Problem 5.5-13) The beam shown in Figure P5.5-13 is laterally braced only at the ends. The 40-kip load is a service live load. Use Fy =50 ksi and determine whether a W12×50 is adequate. a. Use LRFD. b. Use ASD.arrow_forwardAn A36 W14X605 simply supported steel beam with span L=14.4m carries a concentrated service liveload “PLL” at midspan. The beam is laterally supported at supports and its midspan. Consider its beam selfweight to be its service deadload, “w” (use ASEP steel manual for selfweight, w and other section properties). Calculate the maximum service PLL that the beam can carry based on flexure requirement using LRFD? Express your answer in KN in 2 decimal places.arrow_forward5.5-9 The beam shown in Figure P5.5-9 is a W36 x 182. It is laterally supported at A and B. The 300 kip load is a service live load. Using the unfactored service loads, a. Compute Cb. Do not include the beam weight in the loading b. Compute Cb, Include the beam weight in the loadingarrow_forward
- Use A992 steel and select a W shape for the following beam: Simply supported with a 40-foot span, lateral support only at each end, service DL = 2k/ft, service LL is a 25-kips concentrated load at midspan. Don’t forget to check with self-weight. The live load deflection is limited to L/360. Please also check for bending capacity and shear capacity. You may use AISC Table 3-2 and/or Table 3-10 to get started for both, but you will notice that you will need to manually solve with AISC Eq.’s F2-3 and F2-4. Solve using LRFD onlyarrow_forwardProblem: Design a section of a concrete beam reinforced for tension only. The beam is simply supported on a span of 6.00 m and carries a load of 18 KN/m. Use Alternate Method of Design with n = 9. f'c = 20.70 MPa, Fy = 275 MPa. Use b = d/2. Note: Clear concrete cover for the beam: 40 mm Clear spacing between rebars: 25 mm (minimum) Minimum bar size to use as per ACI Code: 16 mm diameter Design for flexure only.arrow_forwardA simply supported beam has a height of 600 mm and a width of 300mm. Determine the maximum safe live load that the beam can carry. The dead load is the beam weight plus a superimposed load of 15 kN/m The stirrup size is 12 mm, the top bars are 2-20 mm and the bottom bars are 5-28 mm. The clear distance between layers of bottom bars is the bar size, 28 mm. Use fc'=30 MPa, Grade 60 (fy=414 MPa) reinforcements and concrete cover of 50 mm.arrow_forward
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