Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.11.7P
To determine
(a)
The W shape for beam AB of the floor system by using LRFD
To determine
(b)
The W shape for beam AB of the floor system by using ASD
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Use A992 steel and select a W shape for typical floor beam AB. Assume that the floorslab provides continuous lateral support. The maximum permissible live load deflection is L/180.The service dead loads consist of a 5-inch thick reinforced concrete floor slab (normal weightconcrete), a partition load of 20 psf, and 10 psf to account for suspended ceiling and mechanicalequipment. Don’t forget to check with self-weight. The service live load is 65 psf. You may useAISC Table 3-2 and/or Table 3-10 to check for bending and shear. Use LRFD only.
Use A992 steel, select a W-shape for the upper girder that spans left to right and picks up the loading from the three floor beams. Assume the beam is simply supported. The maximum permissible live load deflection is L/360. The service dead loads consist of a 5-inch thick reinforced concrete floor slab (normal weight concrete), a partitionload of 25 psf, and 20 psf to account for suspended ceiling and mechanical equipment. Don’t forget to check with self-weight. The service live load is 100 psf. You may use AISC Table 3-2 and/or Table 3-10 to check for bending and shear. Use LRFD only. Take Cb = 1.0. Please show all work to verify that this beam is adequate for bending, shear and deflection
P10.10. A W27×94 section of A572 Grade 50 steel
34 feet long, it is used as a simply supported beam. It is subjected to a factored concentrated load of 90 kips at 12 feet from each support. In addition, the beam is subjected to a factored moment of 340 kips-ft at its left end (counterclockwise). Neglect the self-weight of the beam in the calculations, and check whether the beam is safe according to the LRFD. Lateral support is only provided at the ends and load points.
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
Knowledge Booster
Similar questions
- A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm bf = 209 mm tf = 15.6 mm tw = 10.2 mm k = 32 mm ry = 44.9 mm Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa Ix = 552 x 10^6 MPa Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb.arrow_forwardThe simple-span T-beam shown is part of a floor system of span length 20 ft-0 in. and beam spacing of 8 ft-0 in. o.c. Find the practical moment strength ϕMn. Use f′c=3000 psi and fy=60,000 psi. Assume dt=27 in.arrow_forwardProblem 1. A W30 x 116 beams has the top flange restrained against lateral displacement and rotation and has an unstiffened web. A point load is applied to the top flange at 2m. From the left support. The beam spans 12 m. Use A36 steel with yield strength of Fy = 248 Mpa. b. Compute the maximum value of point load that may be applied without web crippling occurring. d = 762 mm; K = 41.28 mm; bf = 266.7 mm; tf = 21.59 mm; tw = 14.33 mmarrow_forward
- Use Fy= 50 ksi and select a W-shapefor a typical floor beam ABfor the following conditions: Assume that the floor slab provides continuous lateral support. Slab thickness = 5.0 in. (normal-weight concrete) Partition load = 22 psf Weight of ceiling = 7 psf Live load = 100 psf The maximum live load deflection cannot exceed L/360.arrow_forwardSelect a K-series open-web steeljoist for the following conditions: Assume that the floor slab provides continuous lateral support. joists spaced at 3 feet and spanning 26 feet Slab thickness = 4.0 in. (normal-weight concrete) Weight of ceiling = 7 psf Other dead load = 12 psf Live load = 80 psf Partition load = 20 psf The maximum live load deflection cannot exceed L/360.arrow_forwardEXS:Design the cantilever slab shown in the figure below (The figure is top view). The slab carry service dead load is 3 i—’; (not include self weight)and service live load is 5 2% Use effective cover=25mm & use f'; = 27.6MPa, f, = 414Mpa.Neglect the moment & shear for check the depth of the slab. ‘ -] 8marrow_forward
- A 5.5m simple beam carries a uniform ultimate load Wu. The beam is laterally supported and has compact section. The properties of the section are: rx=105.16mm, ry=22.2mm, Sx=308000mm^3, Sy=35000mm^3, Zx=357000mm^3, Zy=55000mm^3, and Fy=248MPa. Calculate the ultimate load capacity Wu of the beam in KN/m considering flexure. Express your answer in 3 decimal places.arrow_forwardQI/ A beam carries the loads shown in figure, if the tensile stress must not exceed 20 MPa and the compression stress 70MPa. Find the maximum value of load P Som, r W=2-5p W/m - P Lflj Ko ; - 3,‘, ) o Jo 1 er -1 /i e,arrow_forwardA flooring system consist of I-beam sections spaced at 3 m(center to center) and with simple spans of 6 m. The beams support a 200 mm thick slab. The flooring system is designed for a live load of 2400 N/m² as well as ceiling load of 750 N/m². The properties of the I-beam sections are : d = 352 mm, weight of beam = 440 N/m, moment of inertia , Ix = 0.0012 m⁴. Consider Fy = 248 MPa, E = 200000 MPa and wt. of concrete of 24 kN/m³. 1. Which of the following most nearly gives the uniform pressure acting on the slab? a. 6.2 kPa b. 7.95 kPa c. 5.2 kPa d. 6.10 kPa 2. Which of the following most nearly gives the total uniform load on the beam in kN/m? a. 19.71 kN/m b. 17.82 kN/m c. 24.29 kN/m d. 28.14 kN/m 3. Which of the following most nearly gives the initial stress on the beam due to deadload only assuming no shoring during construction? a. 12.1 MPa b. 8.91 MPa c. 10.4 MPa…arrow_forward
- A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 59. If the columns sustains a service axial dead load of 1 490 KN Calculate the safe service axial live load in KN by ASD.arrow_forwardA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 60. If the columns sustains a service axial live load of 990 KN calculate the safe service axial dead load in KN by LRFDarrow_forwardThe beam shown in Figure is a W16 x 31 of A992 steel. It supports a reinforced concrete floor slab that provides continuous lateral support of the compression flange. The service dead load is 450 /byft. This load is superimposed on the beam; it does not include the weight of the beam itself. The service live load is 550 lby/ft. Does this beam have adequate moment strength?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning