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Steel Design (Activate Learning wi...

6th Edition
Segui + 1 other
Publisher: Cengage Learning
ISBN: 9781337094740
Chapter 5, Problem 5.11.9P
Textbook Problem
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Same as Problem 5.11-8, but let all the loads on the girder act as a uniform load (be sure to include the weight of the beams).

To determine

(a)

A typical girder for the floor system of problem 5.118 by using LSRD and design.

Explanation of Solution

Given information:

Beam weight wb=35lb/ft

Thickness of slab t=4.5

Live load, wsl=95psf

Distance between two adjacent beams, Lp=5ft

Calculation:

Assuming the girder is supporting beams on each side.

Calculate slab weight,

wslab=t12×150wslab=512×150wslab=62.5psf

Total dead load on the beam is given by

wD=(ws)LpwD=(62.5)5wD=312.5lb/ft

Total live load on the beam is given by

wL=(80+20)LpwL=(100)5wL=500lb/ft

Calculate factored uniformly distributed load on the beam is given by

wu=1

To determine

(b)

A typical girder for the floor system of problem 5.118 by using ASD and design.

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Chapter 5 Solutions

Steel Design (Activate Learning with these NEW titles from Engineering!)
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