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4th Edition

HEALEY + 1 other

Publisher: Cengage Learning,

ISBN: 9781305093836

Chapter 5, Problem 5.1P

To determine

**To find:**

The

Expert Solution

**Solution:**

The

% Area Above | % Area Below | ||

5 | 95.25 | 4.75 | |

6 | 90.82 | 9.18 | |

7 | 84.13 | 15.87 | |

8 | 74.86 | 25.14 | |

9 | 62.93 | 37.07 | |

11 | 37.07 | 62.93 | |

12 | 25.14 | 74.86 | |

14 | 9.18 | 90.82 | |

15 | 4.75 | 95.25 | |

16 | 2.28 | 97.72 | |

18 | 0.38 | 99.62 |

**Given:**

The scores of the quiz are normally distributed with a mean of 10 and standard deviation of 3.

The scores of the quiz are-

**Description:**

The normal curve is symmetrical and its mean is equal to the median. The area below and above the mean is 50% or 0.05.

**Formula used:**

Let the data values be denoted by

The formula to calculate the

Where,

**Calculation:**

Given that the mean is 10 and standard deviation is 3.

For the score of 5,

Substitute 5 for

From the normal distribution table the area below the score of

The area between the mean and the score

Use the concept of symmetry, the area above the score of

The percentage of area below and above the score of

For the score of 6,

Substitute 6 for

From the normal distribution table the area below the score of

The area between the mean and the score

Use the concept of symmetry, the area above the score of

The percentage of area below and above the score of

For the score of 7,

Substitute 7 for

From the normal distribution table the area below the score of

The area between the mean and the score

Use the concept of symmetry, the area above the score of

The percentage of area below and above the score of

For the score of 8,

Substitute 8 for

From the normal distribution table the area below the score of

The area between the mean and the score

Use the concept of symmetry, the area above the score of

The percentage of area below and above the score of

For the score of 9,

Substitute 9 for

From the normal distribution table the area below the score of

The area between the mean and the score

Use the concept of symmetry, the area above the score of

The percentage of area below and above the score of

For the score of 11,

Substitute 11 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

For the score of 12,

Substitute 12 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

For the score of 14,

Substitute 14 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

For the score of 15,

Substitute 15 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

For the score of 16,

Substitute 16 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

For the score of 18,

Substitute 18 for

From the normal distribution table the area above the score of

The area between the mean and the score

Use the concept of symmetry, the area below the score of

The percentage of area above and below the score of

**Conclusion:**

Therefore, the

% Area Above | % Area Below | ||

5 | 95.25 | 4.75 | |

6 | 90.82 | 9.18 | |

7 | 84.13 | 15.87 | |

8 | 74.86 | 25.14 | |

9 | 62.93 | 37.07 | |

11 | 37.07 | 62.93 | |

12 | 25.14 | 74.86 | |

14 | 9.18 | 90.82 | |

15 | 4.75 | 95.25 | |

16 | 2.28 | 97.72 | |

18 | 0.38 | 99.62 |

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