Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
bartleby

Videos

Question
Chapter 5, Problem 5.31E

(a)

Interpretation Introduction

Interpretation:

The proper expression for the equilibrium constant of the reaction is to be stated.

Concept introduction:

Equilibrium constant for a chemical reaction defines the extent of reaction. It is the ratio of concentration of products formed to the concentration of reactants with time which is expressed in terms of activity and molarity. The equilibrium constant is constant at a specified temperature and pure solids and pure liquids are not taken in the expression for equilibrium constant. In order to get a unitless quantity, the whole product is divided by the standard molal concentration.

(a)

Expert Solution
Check Mark

Answer to Problem 5.31E

The expression for equilibrium constant for the reaction PbCl2(s)Pb2+(aq)+2Cl-(aq) is given below.

Keq=[γPb2+mPb2+][γClmCl]2γPbCl2mPbCl2mο

Explanation of Solution

The equilibrium constant for the given reaction can be expressed as the product of the concentration of products as given below.

Keq=[γPb2+mPb2+][γClmCl]2γPbCl2mPbCl2mο

In the above expression, Keq is the equilibrium constant and the square brackets represent the concentrations of products (Pb2+ and Cl-). The power of 2 at [Cl]2 is due to its stoichiometric coefficient in the reaction. The term mο represents the standard molal concentration. Since PbCl2 is in the solid form, so it will be taken as 1 in the equilibrium constant for the reaction.

Conclusion

The equilibrium constant for the given reaction is Keq=[γPb2+mPb2+][γCl-mCl-]2γPbCl2mPbCl2mο.

(b)

Interpretation Introduction

Interpretation:

The proper expression for the equilibrium constant of the reaction is to be stated.

Concept introduction:

Equilibrium constant for a chemical reaction defines the extent of reaction. It is the ratio of concentration of products formed to the concentration of reactants with time which is expressed in terms of activity and molarity. The equilibrium constant is constant at a specified temperature and pure solids and pure liquids are not taken in the expression for equilibrium constant.

(b)

Expert Solution
Check Mark

Answer to Problem 5.31E

The expression for equilibrium constant for the reaction HNO2(aq)H+(aq)+NO2(aq) is given below.

Keq=[γH+mH+][γNO2-mNO2-][γHNO2mHNO2].

Explanation of Solution

The equilibrium constant for the given reaction can be expressed as the ratio of the product of the concentration of products to the product of the concentration of reactants that is:

Keq=[γH+mH+][γNO2mNO2][γHNO2mHNO2]

In the above expression, Keq is the equilibrium constant and the square brackets represent the concentrations of products and reactants, that is H+, NO2 and HNO2. The term mο represents the standard molal concentration. Since the stoichiometric coefficient of the reactants and the product is 1 therefore, it is taken as the direct product.

Conclusion

The equilibrium constant for the given reaction is Keq=[γH+mH+][γNO2-mNO2-][γHNO2mHNO2].

(c)

Interpretation Introduction

Interpretation:

The proper expression for the equilibrium constant of the reaction is to bestated.

Concept introduction:

Equilibrium constant for a chemical reaction defines the extent of reaction. It is the ratio of concentration of products formed to the concentration of reactants with time which is expressed in terms of activity and molarity. The equilibrium constant is constant at a specified temperature and pure solids and pure liquids are not taken in the expression for equilibrium constant.

(c)

Expert Solution
Check Mark

Answer to Problem 5.31E

The expression for equilibrium constant for the given reaction CaCO3(s)+H2C2O4(aq)CaC2O4(s)+H2O(l)+CO2(g) is given below.

Keq=pCO2[γH2C2O4mH2C2O4]

Explanation of Solution

The equilibrium constant for the given reaction can be expressed as the ratio of the product of the concentration of products to the product of the concentration of reactants that is,

Keq=pCO2[γH2C2O4mH2C2O4]

In the above expression, Keq is the equilibrium constant, pCO2 is the partial pressure of carbon dioxide gas evolved as a product in the reaction and [H2C2O4] is the concentration of reactant. The term mο represents the standard molal concentration. In case of gaseous reactants or products, their partial pressure is taken instead of molar concentrations.

Conclusion

The equilibrium constant for the given reaction is Keq=pCO2[γH2C2O4mH2C2O4].

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Write the Ka (acid ionization equilibrium constant) expression for the ionization of HC3H5O2 in water.
Write the expression for the acid-dissociation constant Ka for HC4H7O2. (Concentration equilibrium expressions take the general form: Kc = [C]c / [A]a . [B]b. Subscripts and superscripts that include letters must be enclosed in braces {}.)
For the acid-base equilibrium, idicate the acid-base conjugate pairs.    NH4(aq) + OH(aq)   ➡   NH3(aq)  +  H2O(l)  Hence Justify your answer

Chapter 5 Solutions

Physical Chemistry

Ch. 5 - 5.11. Determine the numerical value of Q for the...Ch. 5 - 5.12. True or false: If all the partial pressures...Ch. 5 - For the reaction 2SO3(g)2SO2(g)+O2(g) when 2mol of...Ch. 5 - 5.14. Determine and for the following reaction at...Ch. 5 - 5.15. Consider the reaction If the partial...Ch. 5 - 5.16. In atmospheric chemistry, the following...Ch. 5 - Prob. 5.17ECh. 5 - 5.18. Hydrogen cyanide can isomerize to hydrogen...Ch. 5 - 5.19. Assume that a reaction exists such that...Ch. 5 - Prob. 5.20ECh. 5 - 5.21. Show that if the coefficients of a balanced...Ch. 5 - 5.22. True or false: If for a gas-phase reaction,...Ch. 5 - 5.23. The balanced chemical reaction for the...Ch. 5 - The answers in exercise 5.23 should show that...Ch. 5 - At a high enough temperature, the equilibrium...Ch. 5 - Prob. 5.26ECh. 5 - 5.27. Nitrogen dioxide,, dimerizes easily to form...Ch. 5 - 5.28. Another nitrogen-oxygen reaction of some...Ch. 5 - Prob. 5.29ECh. 5 - Prob. 5.30ECh. 5 - Prob. 5.31ECh. 5 - 5.32. For the reaction . (a) Using in Appendix...Ch. 5 - 5.33. Use the data in Appendix to calculate ...Ch. 5 - 5.34. The of diamond, a crystalline form of...Ch. 5 - 5.35. The densities of graphite and diamond are ...Ch. 5 - Buckminsterfullerene, C60, is a spherical molecule...Ch. 5 - Prob. 5.37ECh. 5 - At what pressure does H2O have an activity of...Ch. 5 - The bisulfate or hydrogen sulfate anion, HSO4, is...Ch. 5 - Prob. 5.40ECh. 5 - Write the equilibrium constant expression for each...Ch. 5 - Prob. 5.42ECh. 5 - For the given chemical equilibrium, these data are...Ch. 5 - Biological standard states include specifying a...Ch. 5 - a At 25.0C, Kw for the autoionization of water is...Ch. 5 - 5.46. For a reaction whose standard enthalpy...Ch. 5 - 5.47. For the reaction and . Estimate for this...Ch. 5 - 5.48. The isotope exchange reaction has an...Ch. 5 - 5.49. Consider the following equilibrium: What...Ch. 5 - 5.50. For the equilibrium Equilibrium partial...Ch. 5 - The decomposition of NaHCO3, used in kitchens to...Ch. 5 - 5.52. For the equilibrium at,. In a flask, of...Ch. 5 - Prob. 5.53ECh. 5 - 5.54. For the reaction The equilibrium...Ch. 5 - Prob. 5.55ECh. 5 - 5.56. Of the amino acids listed in Table , which...Ch. 5 - 5.57. Determine the concentration of the three...Ch. 5 - 5.58. The formation of zwitterionic glycine, ,...Ch. 5 - 5.59. Monosodium glutamate, or MSG, is the sodium...Ch. 5 - Prob. 5.60ECh. 5 - Consider the balanced chemical reaction...Ch. 5 - For the gas-phase reaction 2H2+O22H2O rxnG is...Ch. 5 - Prob. 5.63ECh. 5 - Prob. 5.64E
Knowledge Booster
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
    • SEE MORE QUESTIONS
    Recommended textbooks for you
  • Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Chemistry by OpenStax (2015-05-04)
    Chemistry
    ISBN:9781938168390
    Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
    Publisher:OpenStax
  • General, Organic, and Biological Chemistry
    Chemistry
    ISBN:9781285853918
    Author:H. Stephen Stoker
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
  • Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Chemistry by OpenStax (2015-05-04)
    Chemistry
    ISBN:9781938168390
    Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
    Publisher:OpenStax
    General, Organic, and Biological Chemistry
    Chemistry
    ISBN:9781285853918
    Author:H. Stephen Stoker
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY