   Chapter 5, Problem 53P

Chapter
Section
Textbook Problem

The electric motor of a model train accelerates the train from rest to 0.620 m/s in 21.0 ms. The total mass of the train is 875 g. Find the average power delivered to the train during its acceleration.

To determine
The average power delivered to the train during the acceleration.

Explanation

Given Info:

Initial velocity is zero.

Final velocity is 0.620m/s .

The time of acceleration is 21.0ms .

The mass of train is 875.0g .

According to Work-Energy theorem,

Wnc=(KE+PE)f(KE+PE)i

Consider the train is moving in a leveled track.

Thus,

Wnc=12m(vf2vi2)       (I)

• vf is the final velocity
• vi is the initial velocity
• m is the mass of the train

Formula to calculate the power delivered by the train is,

P=WncΔt

• Δt is the time of acceleration

Substitute equation (I) in (II),

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