   # What mass of phosphorus is present in 5.00 moles of each of the compounds in Exercise 52? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 58E
Textbook Problem
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## What mass of phosphorus is present in 5.00 moles of each of the compounds in Exercise 52?

(a)

Interpretation Introduction

Interpretation: The number of moles of compound is given. By using the number of moles, the mass of phosphorous in each compound given in exercise 52 is to be determined.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

To determine: The mass of phosphorous (P) in 5.00 moles of P4O6 .

### Explanation of Solution

Given

The moles of P4O6 is 5.00 .

Since, one mole of P4O6 is equal to four moles of phosphorous (P) therefore, 5.00 moles of P4O6 is equal to,

4×5.00mol=20.00mol of P .

The atomic mass of phosphorous (P) is 30.973g/mol .

Formula

The mass of phosphorous (P) in P4O6 is calculated using the formula,

MolesofP=Massof

(b)

Interpretation Introduction

Interpretation: The number of moles of compound is given. By using the number of moles, the mass of phosphorous in each compound given in exercise 52 is to be determined.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

(c)

Interpretation Introduction

Interpretation: The number of moles of compound is given. By using the number of moles, the mass of phosphorous in each compound given in exercise 52 is to be determined.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

To determine: The mass of phosphorous (P) in 5.00 moles of Na2HPO4 .

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