   # If 0.10 mol of I 2 vapor can effuse from an opening in a heated vessel in 39 s, how long will it take 0.10 mol H 2 to effuse under the same conditions? ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

#### Solutions

Chapter
Section ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343
Chapter 5, Problem 5.97QP
Textbook Problem
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## If 0.10 mol of I2 vapor can effuse from an opening in a heated vessel in 39 s, how long will it take 0.10 mol H2 to effuse under the same conditions?

Interpretation Introduction

Interpretation:

The time taken for effusion of 0.10 mol H2 under the given conditions has to be calculated

Concept Introduction:

Root-mean-square (rms):

The root-mean-square molecular speed (u) is given by the below formula.

u  =3RTMm =(3RTMm)12

Where,

R is the molar gas constant

T is the absolute temperature

Mm is the molar mass of the gas

Graham’s law of effusion:

Rate of effusion of molecules  1Mm

Where,

Mm is the molar mass of the gas

### Explanation of Solution

To Calculate: The time taken for effusion of 0.10 mol H2 under the given conditions

Given,

0.10 mol of I2 vapor effuse from an opening in a heated vessel in 39 s.

Time taken for effusion of Hydrogen:

The rates of effusion are directly related to the rms speed.

Make an assumption that the temperature is the same for both the molecules and write a ratio of two Maxwell distributions.

The molar mass of H2 is Mm(H2) = 2.016 g/mol

The molar mass of I2 is Mm(I2) = 253.8 g/mol

uH2uI2  = (3RTMm(H2))12<

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