   Chapter 5, Problem 5P

Chapter
Section
Textbook Problem

Starting from rest, a 5.00-kg block slides 2.50 m down a rough 30.0° incline. The coefficient of kinetic friction between the block and the incline is μk = 0.436. Determine (a) the work done by the force of gravity, (b) the work done by the friction force between block and incline, and (c) the work done by the normal force. (d) Qualitatively, how would the answers change if a shorter ramp at a steeper angle were used to span the same vertical height?

(a)

To determine
The work done by the force of gravity.

Explanation

Given Info:

The mass of the block is 5.00kg .

The length of the surface that the block slides is 2.50m .

The inclination of the surface is 30.0° .

Formula to calculate the work done is,

W=(Fcosθ)d       (I)

• θ is the angle between the force vector and the displacement vector
• F is the force
• d is the magnitude of displacement

Since, the gravitational force acting on the object is,

F=mg

• m is the mass of the block
• g is acceleration due to gravity

Thus, equation (I) gives,

W=(mgcosθ)d

Substitute 5

(b)

To determine
The work done by the friction force between the block and the incline.

(c)

To determine
The work done by the normal force.

(d)

To determine
how would the answers change if a shorter ramp at a steeper angle were used.

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