   Chapter 5, Problem 60P

Chapter
Section
Textbook Problem

An object of mass 3.00 kg is subject to a force Fx that varies with position as in Figure P5.60. Find the work done by the force on the object as it moves (a) from x = 0 to x = 5.00 m, (b) from x = 5.00 m to x = 10.0 m, and (c) from x = 10.0 m to x = 15.0 m. (d) If the object has a speed of 0.500 m/s at x = 0, find its speed at x = 5.00 m and its speed at x = 15.0 m. Figure P5.60

(a)

To determine
The work done by the force on the object when the object moves from x=0m to x=5m .

Explanation

Given Info:

The particle is moving from x equals to 0 to 5m .

The work done by the force on the object is the area under the cure in the force verses displacement graph.

Thus, the work done on the object when it travels from A to B in the graph is equal to the area under the graph A to B.

Formula to calculate the work done is,

W05=12bh

• b is the base of the triangle
• h is the height of the triangle

Substitute 5m for b and 3.0N for h to find the work done,

W05=12(5

(b)

To determine
The work done by the force when the object moves in the path from 5m to 10m .

(c)

To determine
The work done by the force on the object when the object moves from x=10m to x=15m .

(d)

To determine
The speed of the object at x=5m and x=15m .

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