   Chapter 5, Problem 64PS

Chapter
Section
Textbook Problem

The enthalpy change for the oxidation of styrene. C8H8, is measured by calorimetry.C8H8(ℓ) + 10 O2(g) → 8 CO2(g) + 4 H2O(ℓ)ΔrH° = –4395.0 kJ|/mol-rxnUse this value, along with the standard enthalpies of formation of CO2(g) and H2O(ℓ), to calculate the enthalpy of formation of styrene. in kJ/mol.

Interpretation Introduction

Interpretation:

The enthalpy of formation of styrene has to be determined.

Concept Introduction:

The standard enthalpy of formation is the enthalpy change for the formation of 1mol of the compound directly from its component elements in their standard states.

Enthalpy change for the reaction ΔrH0=ΣnΔfH0(products)-ΣnΔfH0(reactants)

Explanation

Given,

ΔfH0(CO2)=-393.50kJ/mol

ΔfH0(H2O)=-285.83kJ/mol

ΔrH0=-4395.0kJ

Substitute for the equation,ΔrH0=ΣnΔfH0(products)-ΣnΔfH0(reactants)

-4395

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