   Chapter 5, Problem 64RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Evaluating a Definite Integral In Exercises 59–70, evaluate the definite integral. ∫ 0 3 ( 2 x − 3 ) 2   d x

To determine

To calculate: The definite integral 03(2x3)2dx.

Explanation

Given Information:

The provided definite integral is 03(2x3)2dx.

Formula used:

The power rule of integrals:

undu=un+1n+1+C

The fundamental theorem of calculus:

abf(x)dx=F(b)F(a)

Here, F is function such that F(x)=f(x) for all x in [a,b].

Calculation:

Consider the indefinite integral:

03(2x3)2dx

Rewrite integration as:

1203(2x3)22dx

Now apply general power rule of integration;

1203(2x3)22d

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