A block of mass 14.0 kg slides from rest down a frictionless 40.0° incline and is stopped by a strong spring with k = 2.30 ✕ 104 N/m. The block slides 3.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

Q: A glider of mass 0.240 kgkg is on a frictionless, horizontal track, attached to a horizontal spring…

A: Potential energy of a spring stretched by some distance 'x' is 12kx2 Kinetic energy is given by the…

Q: 50 N/m ell kg x = -0.3 m x= 0 m x= 0.3 m A block of mass 0.5 kg on a horizontal surface is attached…

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Q: A block of mass 11.8 kg slides from rest down a frictionless 35.6∘∘ incline and is stopped by a…

A: Since the incline is frictionless and no other non-conservative forces are acting on the system, the…

Q: A spring (k = 193.7 n/m) is compressed 1.35 m by a block of mass 5 kg. The system is released from…

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Q: A 2.00-kg block is pushed against a spring with negligible mass and force constant compressing it…

A: The expression to determine the total energy of the block at the top of plane is, Et=Ut+Kt

Q: A 2.50 kg textbook is forced against a horizontal spring of negligible mass and having a spring…

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Q: L k = 100 N/m ell e 1.0 kg X = -0.5 m x = 0.0 m x = 0.5 m A block of mass 1.0 kg on a horizontal…

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Q: A block of mass 15.0 kg slides from rest down a frictionless 40.0° incline and is stopped by a…

A: Given:Mass of the block, m = 15 kgInclination of the plane = 40 degreesSpring constant, k = 3.4 ×104…

Q: In the figure, a block of mass m = 3.30 kg slides from rest a distance d down a frictionless incline…

A: Mass (m) = 3.3kg   θ = 35.0 ˚ ( Angle of inclination)   Spring constant (k)= 450N/m  Compression (x)…

Q: A 2.00-kg block is pushed against a spring with negligible mass and force constant compressing it…

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Q: A 1.30 kg block slides on a frictionless horizontal surface until it encounters a spring with a…

A: Given: The mass of the object is 1.3 kg. The spring constant is 520 N/m. The compression in the…

Q: An elevator car of mass 775 kg falls from rest 2.80 m, hits a buffer spring, and then travels an…

A: Given data: The mass of elevator car is m=775 kg. The distance traveled is h=2.80 m. The…

Q: A mass m = 16 kg rests on a frictionless table and accelerated by a spring with spring constant k =…

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Q: A block of mass m = 1.75 kg slides along a horizontal table www with speed vo = 3.50 m/s. At x = 0,…

A: Given Data Mass of the block is m=1.75 kg Initial speed of the block is v0=3.50 m/s Spring constant…

Q: A block of mass m = 2.25 kg slides along a horizontal ww table with speed vo = 10.00 m/s. At x = 0,…

A: The mass of the block is m = 2.25 kg. The speed with which the block slides along a horizontal table…

Q: A block of mass 250.0 g is placed on top of a light vertical spring of constant k = 4.80 x 103 N/m…

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Q: A block of mass 0.5 kg is initially resting against the spring, compressing the spring at a distance…

A: mass of block (m) = 0.5 kg spring constant (k) = 400 Nmcompression in the spring (∆x) = 15 cm = 0.15…

Q: spring with a constant of 50.0 N/cm. The launcher is prepared by compressing the spring by 5.00 cm.…

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Q: A block of mass 100 g, resting on a frictionless surface, is pushed up against a spring compressing…

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Q: A block of mass m-0.25 kg initially moving with= 4 m/s on a smooth surface hits a spring of k= 10000…

A: Hai as per our guidelines we are suppose to answer only one question. Kindly repost other question…

Q: 7.39 A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing…

A: First we need to find work done due to friction

Q: A block of mass 11.0 kg slides from rest down a frictionless 36.0° incline and is stopped by a…

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Q: 2M Two blocks, of masses M = 4.0 kg and 2M, are connected to a spring of spring constant k = 150 N/m…

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Q: The potential energy of an object of m = 3 (kg) moving along the x-axis is given by U(x) =- (). the…

A: Given: Mass, m=3 kg Total mechanical energy, E=10 J Potential energy, Ux=x44-x22 J Concept:…

Q: A block of mass m=0.25 kg starts at rest at the top of an inclined plane of height h=0.8 m as shown…

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Q: A bullet with mass 4.74 g is fired horizontally into a 2.131 kg block attached to a horizontal…

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Q: A 2.50-kg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Using work-energy theorem Kf+Uf-Wnc=Ki+Ui0+0+μkmgd=0+12kx2d=kx22μkmg

Q: A 120 g arrow is shot vertically from a bow whose effective spring constant is 430 N/m. If the bow…

A: Given data: Mass (m) = 120 g = 0.120 kg Spring constant (k) = 430 N/m Spring compressed by distance…

Q: The spring in a dart gun has a spring constant of 20.0 N/m. The spring is compressed 8.00 x 10-2 m…

A: Given data: Spring constant (k) = 20.0 N/m Compression in spring (x) = 8.00 × 10-2 m Mass of dart…

Q: A 2.00-kg block is pushed against a spring with negligible mass and force constant compressing it…

A: The expression to determine the total energy of the block after compressing it is given by, Ec=Kc+Uc

Q: A block of mass 15.0 kg slides from rest down a frictionless 33.0° incline and is stopped by a…

A: mass, m = 15 kg  Angle, A = 33°  k= 4 x 104 N/m distance, d= 3 m

Q: leased. During the launching, the airplane engine exerts a constant horizontal force of 2,000 lbs.…

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Q: A block with a mass of 30.0 kilograms (kg) is held against a spring with a force constant of k =…

A: Work energy theorem states that the work done on a particle by the resultant force is equal to the…

Q: The block of mass m 1.60 kg slides along the horizontal rough plane as shown in the figure. The…

A: We solve this problem using conservation of energy

Q: A block of mass 3.63 Kg slides on a frictionless horizontal tablet at a speed of 1.22 m/s. It comes…

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Q: A box with mass m=3.0 kg is attached to the lower end of a relaxed vertical spring of force constant…

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Q: Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an…

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Q: A 46 g ice cube can slide up and down a frictionless 38° slope. At the bottom, a spring with spring…

A: Given m = 46g =0.046kg Δx = 6cm = 0.06m K = 24N/m

Q: You are an industrial engineer with a shipping company. As part of the package-handling system, a…

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Q: A 1.30 kg block slides on a frictionless horizontal surface until it encounters a spring with a…

A: Given, mass of the block, m = 1.30 kg Force constant, k = 520 Nm compression, x = 2.50 cm

Q: A block of mass m = 0.6 kg slides on a horizontal rough surface head on into a spring of spring…

A: Given:  Block's mass, m=0.6 kg Block distance from spring, x=1.1 m Block velocity, v=3.82 m/s Spring…

Q: The massless spring of a spring gun has a force constant k = 12 N/cm. When the gun is aimed…

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Q: 3.0 kg -400 N/m 3.4 m A 3 kg block placed top of a 3.4 m high ona surface with 0.2 coefficient of…

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Q: A box of mass 10 kg slides along a frictionless surface with a velocity of v = 8.0 m/s and hits a…

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Q: A block of mass m 2.00 kg slides along a horizontal table with speed vo 9.50 m/s. At x = 0 it hits a…

A: Given:Mass of the block, m = 2.00 kgSpeed of the block, V0 = 9.50 m/sSpring constant, K = 95…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.