   # Express the composition of each of the following compounds as the mass percents of its elements. a. formaldehyde, CH 2 O b. glucose, C 6 H 12 O 6 c. acetic acid, HC 2 H 3 O 2 ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 79E
Textbook Problem
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## Express the composition of each of the following compounds as the mass percents of its elements.a. formaldehyde, CH2Ob. glucose, C6H12O6c. acetic acid, HC2H3O2

(a)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in the given compounds CH2O,C6H12O6 and HC2H3O2 is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in formaldehyde (CH2O) compound.

### Explanation of Solution

The atomic weight of carbon (C) is 12.01g/mol . In the compound CH2O , only one carbon atom is present. Hence, mass of carbon in CH2O is 12.01g/mol .

The atomic weight of oxygen (O) is 15.999g/mol . In the compound CH2O , only one oxygen atom is present. Hence, mass of oxygen in CH2O is 15.999g/mol .

The atomic weight of hydrogen (H) is 1.008g/mol . In the compound CH2O , two hydrogen atoms are present. Hence, mass of hydrogen in CH2O is,

2×1.008g/mol=2.016g/mol

The molar mass is the sum of mass of individual atoms present in it.

Hence, molar mass of CH2O is calculated as,

12.01g/mol+15.999g/mol+2.016g/mol=30.025g/mol

Formula

The mass percent of element is calculated as,

Mass%ofelement=MassofelementMolarmassofcompound                                         (1)

Substitute the values of mass of carbon and molar mass of CH2O in the above equation.

Mass%ofCatom=MassofCatomMolarmassofCH2O=(12

(b)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in the given compounds CH2O,C6H12O6 and HC2H3O2 is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in glucose (C6H12O6) compound.

(c)

Interpretation Introduction

Interpretation: The percentage composition (by mass) of each element in the given compounds CH2O,C6H12O6 and HC2H3O2 is to be calculated.

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

Molar mass of a substance is defined as the mass of the substance in gram of one mole of that compound.

The molar mass of any compound can be calculated by adding of atomic weight of individual atoms present in it.

To determine: The percentage composition (by mass) of each element in acetic acid (HC2H3O2) compound.

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