   # You drink 350 mL of diet soda that is at a temperature of 5 °C. (a) How much energy will your body expend to raise the temperature of this liquid to body temperature (37 °C)? Assume that the density and specific heat capacity of diet soda are the same as for water. (b) Compare the value in part (a) with the caloric content of the beverage. (The label says that it has a caloric content of 1 Calorie.) What is the net energy change in your body resulting from drinking this beverage? (1 Calorie = 1000 kcal = 4184 J.) (c) Carry out a comparison similar to that in part (b) for a nondiet beverage whose label indicates a caloric content of 240 Calories. ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 5, Problem 88GQ
Textbook Problem
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## You drink 350 mL of diet soda that is at a temperature of 5 °C. (a) How much energy will your body expend to raise the temperature of this liquid to body temperature (37 °C)? Assume that the density and specific heat capacity of diet soda are the same as for water. (b) Compare the value in part (a) with the caloric content of the beverage. (The label says that it has a caloric content of 1 Calorie.) What is the net energy change in your body resulting from drinking this beverage? (1 Calorie = 1000 kcal = 4184 J.) (c) Carry out a comparison similar to that in part (b) for a nondiet beverage whose label indicates a caloric content of 240 Calories.

(a)

Interpretation Introduction

Interpretation:

The amount of energy required to raise the temperature has to be determined

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1k. Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q = energy gained or lost for a given mass of substance (m), C =specific heat capacity,ΔT= change in temperature.

### Explanation of Solution

Given,

Volume=350mL

Mass=350g

C=4.184J/gK

ΔT=32K

Substitute in q=C×m×ΔT as

q=350g×4

(b)

Interpretation Introduction

Interpretation:

The net energy change in our body has to be identified.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1k. Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q = energy gained or lost for a given mass of substance (m), C =specific heat capacity,ΔT= change in temperature.

(c)

Interpretation Introduction

Interpretation:

The net energy change in our body for nondiet beverage has to be identified.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1k. Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q = energy gained or lost for a given mass of substance (m), C =specific heat capacity,ΔT= change in temperature.

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