Chapter 5.1, Problem 5.1Q

(a)

Interpretation Introduction

Interpretation:

Given pressure unit of $\text{725}\text{mm}\text{Hg}$ has to be expressed in terms of $\text{atm}$.

Concept Introduction:

Units of pressure can be converted into other units by using the conversion factor.  It is known that $\text{1}\text{atm}$ of pressure is equal to $\text{760}\text{mm Hg}$.  Conversion factors can be given as,

    $\frac{\text{1 atm}}{\text{760}\text{mm}\text{Hg}}\text{or}\frac{\text{760 mm Hg}}{\text{1 atm}}$

(b)

Interpretation Introduction

Interpretation:

Given pressure unit of $\text{29}\text{.0}\text{cm}\text{Hg}$ has to be expressed in terms of $\text{atm}$.

Concept Introduction:

Units of pressure can be converted into other units by using the conversion factor.  It is known that $\text{1}\text{atm}$ of pressure is equal to $\text{76}\text{.0}\text{cm Hg}$.  Conversion factors can be given as,

    $\frac{\text{1 atm}}{\text{76}\text{cm}\text{Hg}}\text{or}\frac{\text{76 cm Hg}}{\text{1 atm}}$

(c)

Interpretation Introduction

Interpretation:

Given pressure unit of $\text{555 torr}$ has to be expressed in terms of $\text{atm}$.

Concept Introduction:

Units of pressure can be converted into other units by using the conversion factor.  It is known that $\text{1}\text{atm}$ of pressure is equal to $\text{760 torr}$.  Conversion factors can be given as,

    $\frac{\text{1 atm}}{\text{760}\text{torr}}\text{or}\frac{\text{760 torr}}{\text{1 atm}}$

(d)

Interpretation Introduction

Interpretation:

Given pressure unit of $\text{95}\text{psi}$ has to be expressed in terms of $\text{atm}$.

Concept Introduction:

Units of pressure can be converted into other units by using the conversion factor.  It is known that $\text{1}\text{atm}$ of pressure is equal to $\text{14}{\text{.7 lb/in}}^{\text{2}}$.  Conversion factors can be given as,

    $\frac{\text{1 atm}}{\text{14}\text{.7}\text{psi}}\text{or}\frac{\text{14}\text{.7 psi}}{\text{1 atm}}$