   Chapter 5.2, Problem 20E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Applying the General Power Rule In Exercises 9-34, find the indefinite integral. Check your result by differentiating. See Examples 1, 2, 3, and 5. ∫ x ( 7   -   6 x 2 ) 5   d x

To determine

To calculate: The value of the provided indefinite integral x(76x2)5dx.

Explanation

Given Information:

The provided indefinite integral is x(76x2)5dx.

Formula Used:

According to the general power rule for integration,

If u is a differentiable function of x, then

undu=un+1n+1+C,

where n1

Calculation:

Consider the indefinite integral say I,

I=x(76x2)5dx

Multiply and divide by -12 in the right-hand side of above integral;

I=1(12)(12x)(76x2)5dx

Take the factor 112 out of the integrand;

I=112(12x)(76x2)5dx

Let

76x2=u … (1)

Differentiate the above equation with respect to x;

ddx(76x2)=dudxddx(7)ddx(6x2)=dudx12x=dudx

Or

(12x)dx=du … (2)

Substitute the values

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Evaluate the integral. 10102exsinhx+coshxdx

Single Variable Calculus: Early Transcendentals

#### 12,554+22,606+11,460+20,005+4,303=

Contemporary Mathematics for Business & Consumers

#### 0 2 −2 does not exist

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th

#### It does not exist.

Study Guide for Stewart's Multivariable Calculus, 8th 