   Chapter 5.3, Problem 16QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 15–20, find the indefinite integral. ∫ 9 x 2 e x 3 d x

To determine

To calculate: The indefinite integral 9x2ex3dx.

Explanation

Given Information:

The provided indefinite integral is 9x2ex3dx.

Formula used:

The exponent rule of integrals:

eudu=eu+C

Calculation:

Consider the indefinite integral:

9x2ex3dx

Let u=x3, then derivative will be,

du=d(x3)=3x2dx

Rewrite above indefinite integration as:

3ex3(3x2dx)

Substitute du for 3x2dx and u for x3 in provided integration

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