   Chapter 5.3, Problem 34E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding indefinite integrals In Exercises 31–46, use any basic integration formula or formulas to find the indefinite integral. State which integration formula(s) you used to find the integral. ∫ 2 x 3 − 6 x 2 − 5 x x 2   d x

To determine

To calculate: The indefinite integral 2x36x25xx2dx.

Explanation

Given Information:

The provided indefinite integral is 2x36x25xx2dx.

Formula used:

The logarithmic rule of integrals:

duu=ln|u|+C

The general power rule of integrals:

undudxdx=un+1n+1+C (for n1)

The constant rule of integrals:

cdu=cdu

Calculation:

Consider the indefinite integral:

2x36x25xx2dx

Now, simplify the integrand,

2x36x25xx2dx=(2x3x26x2x25xx2)dx

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