Chapter 5.3, Problem 40E

### Calculus: Early Transcendental Fun...

7th Edition
Ron Larson + 1 other
ISBN: 9781337552516

Chapter
Section

### Calculus: Early Transcendental Fun...

7th Edition
Ron Larson + 1 other
ISBN: 9781337552516
Textbook Problem

# Using Properties of Definite Integrals In Exercises 37-44, evaluate the definite integral using the values below. ∫ 2 6 x 3 d x = 320 , ∫ 2 6 x   d x = 16 , ∫ 2 6 d x = 4 ∫ 2 6 − 3 x   d x

To determine

To calculate: The definite integral 263xdx using the provided values

26x3dx=32026xdx=1626dx=4

Explanation

Given:

The provided values are:

âˆ«26x3dx=320âˆ«26xdx=16âˆ«26dx=4

And the integral to be find out is:

âˆ«26âˆ’3xdx

Formula used:

Constant multiple rule for integration:

âˆ«abkf(x)dx=kâˆ«abf(x)dx

Calculation:

âˆ«26âˆ’3xdx

Apply the constant multiple rule

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