   Chapter 5.3, Problem 48E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Finding an Equation of a Function In Exercises 47–50, find an equation of the function f that has the given derivative and whose graph passes through the given point. f ' ( x ) = 2 1 + e − x ;   ( 0 ,   3 )

To determine

To calculate: The equation of function f(x) that has derivative f(x)=21+ex and whose graph passes through the point (0,3).

Explanation

Given Information:

The first derivative f(x)=21+ex.

The coordinate of point (0,3).

Formula used:

The general exponent rule of integrals:

eu(x)du(x)=ln|u(x)|+C

Here, u is function of x.

The property of Intro-differential:

df(x)dxdx=f(x)

Calculation:

Consider the derivative:

f(x)=21+ex

Rewrite the integrand as:

df(x)dx=21+ex=2exex+1

Apply, integration on both sides:

df(x)dxdx=2exex+1dx

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Solve the equations in Exercises 126. 14x2=0

Finite Mathematics and Applied Calculus (MindTap Course List)

#### In Exercises 3540, rationalize the numerator of each expression. 36. y3x

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### In problems 37-44, perform the indicated operations and simplify. 41.

Mathematical Applications for the Management, Life, and Social Sciences

#### It does not exist.

Study Guide for Stewart's Multivariable Calculus, 8th 